Answer: The volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is LiOH.
We are given:
Putting values in above equation, we get:
Thus the volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml
The required temperature of the sample of gas is 823K.
<h3>What is ideal gas equation?</h3>
Ideal gas equation gives idea about the behavior of gas at different condition & represented as:
PV = nRT, where
- P = pressure = 500 torr = 0.657 atm
- V = volume = 5.01 L
- R = universal gas constant = 0.082 L.atm / K.mol
- T = temperature = ?
- n = moles
Moles will be calculated as:
n = W/M, where
- W = given mass
- M = molar mass
Moles of Neon gas = 1g / 20.1g/mol = 0.049 mole
On putting all these values in the above equation, we get
T = (0.657)(5.01) / (0.049)(0.082) = 822.8 = 823 K
Hence required temperature of the sample is 823 K.
To know more about ideal gas equation, visit the below link:
brainly.com/question/21912477
#SPJ1
The mass percentage of KCl solution is 21.34%
Calculation,
Given molality of KCl aqueous solution = 3. 64 m = 3. 64 mole/ Kg
It means 3. 64 mole of solute present in 1Kg of solvent
or , 3. 64 mole of solute present in 1000 g of solvent ( water )
Mass of solute ( KCl ) = 3. 64 mole×74.55 g/mole =271.3 g
The total mass of solution ( KCl + water ) = 271.3 g + 1000 g = 1271.3 g
Mass percentage is equal to percentage of mass of solute present in total mass of solution.
Mass percentage = 100×271.3 g/1271.3 g = 21.34%
to learn more about mass percentage
brainly.com/question/27108588
#SPJ4
Answer A: Connect a wire coil to an ammeter. Move a bar magnet into and out of the wire coil as you observe the ammeter.
Answer:
B) Crust
Explanation:
It's the farthest layer from the core listed.
