Question

Construct a simulated 1H NMR spectrum, including proton integrations, for CH3OC(CH2OCH3)3 (see Hint). Drag the appropriate splitting patterns to the approximate chemical shift positions; place the integration values in the small bins above the associated chemical shift. Splitting patterns and integrations may be used more than once, or not at all, as needed. Likewise, some bins might remain blank. Note that peak heights are arbitrary and do not indicate proton integrations.

Answer 1

Answer:

The drawing of the structure is found in diagram 1 of the attached figure.

Explanation:

Diagram 1 shows that three different types of protons are found in the structure. The nine hydrogen atoms have a similar behavior, the six hydrogen atoms also have a similar behavior and finally, the three hydrogen atoms adjacent to oxygen have a similar behavior. The number of peaks are as follows:

9H = singlet peak = between 3 and 4 ppm

6H = singlet peak = 4 ppm

3H = singlet peak = 3 ppm.

The 9 protons are around 3.5 ppm and the 6 hydrogen atoms show a peak at 4 ppm, and finally, the 3 protons have a peak around 3 ppm. Therefore, the corresponding drawing can be seen in diagram 2.