0.24J/g*degC * 4.37g * 2.5degC = 2.622J
The 2.5 degC is the difference between 25 and 27.5 deg C.
The correct answer to this question is this one:
find the energy of one photon:
<span>E=h*<span>c/λ
</span></span>
divide the energy given by the energy of one photon of that wavelength
What I've done so far is convert wave length to m and energy to j.
E photon = h * x / wave length
E = (6.626 x 10^-43)(3.00 x 10^8) / 587 ^ -9 = 3.38 x 10 ^18 J
3.38 x 10 ^18 J x 1000 kj / 1 j = 3.37 x 10 ^ 16 Kj
609 kJ/ 3.37 x 10 ^ 16 Kj = 1.81 x 10 ^ 16
E = (6.626 x 10^-34)(3.00 x 10^8) / 587 ^ -9 = 3.38 x 10 ^19 J
3.38 x 10 ^19 J x 1000 kj / 1 j = 3.37 x 10 ^ -16 Kj
609 kJ/ 3.37 x 10 ^ 16 Kj = 1.81 x 10 ^ 18 but the answer is 1.81 × 10^24 photons
3.38 x 10 ^-19 J
should be negative
then 3.38 x 10 ^18 J x 1kJ/1000 J
you're converting from J to kJ.. just like meters to kilometres, you wouldn't multiply you would divide
Answer:
18.2784 g
Explanation:
First we <u>convert 180 lb to kg</u>:
- 180 lb * 0.453 kg / lb = 81.6 kg
Now we <u>calculate the mass of antibiotic taken in one day</u>:
- 8.0 mg/kg * 81.6 kg = 652.8 mg
Given that it is taken twice daily, <em>in one day the person would take (652.8 * 2) 1305.6 mg</em>. In grams that mass would be:
- 1305.6 mg / 1000 = 1.3056 g
Finally we multiply those 1.3056 daily grams by the 14 days in two weeks:
- (1.3056 g) * 14 = 18.2784 g
Answer:
Explanation:
Hello there!
In this case, according to the given information and chemical equation, it turns out possible for us to calculate the moles of C2O4^2- by firstly setting up the equilibrium expression:
However, according to the question, we just need to apply the given 1:3 mole ratio in the chemical reaction, of iron (III) ions to oxalate ions to obtain:
Regards!