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kap26 [50]
4 years ago
12

Choose all that correctly define the point on the directed line segment between the two given points that partitions the segment

in the given ratio. Line segment AB has endpoints A(8, 4) and B(4, 8). The coordinates (7, 5) divides the line segment directed from A to B in the ratio of 1:3. Line segment AB has endpoints A(1, 2) and B(9, 10). The coordinates (4, 3) divides the line segment directed from A to B in the ratio of 1:3. Line segment AB has endpoints A(1, 3) and B(5, 15). The coordinates (6, 2) divides the line segment directed from A to B in the ratio of 1:3. Line segment AB has endpoints A(0, 12) and B(8, 8). The coordinates (2, 11) divides the line segment directed from A to B in the ratio of 1:3.
Mathematics
2 answers:
Flura [38]4 years ago
4 0

Answer:

A(1, 3) and B(5, 15). The coordinates (6, 2) divides the line segment directed from A to B in the ratio of 1:3. Line segment AB has endpoints A(0, 12) and B(8, 8). The coordinates (2, 11) divides the line segment directed from A to B in the ratio of 1:3.

Step-by-step explanation:

Thanks you are lucky you just gave me 405 points add me and you earn 50

34kurt4 years ago
4 0

Answer:

A and D

Step-by-step explanation:

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Name the possible rational roots for the function using the Rational Root Theorem.
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Answer:

\pm 1,\pm 3,\pm 5,\pm 15,\pm \frac{1}{3},\pm \frac{5}{3}

Step-by-step explanation:

Given:

The function is given as:

f(x)= 3x^{3}-19x^{2} +23x-15

The possible rational roots for a function f(x) = a_{n}x^{n}-a_{n-1}x^{n-1} +a_{n-2}x^{n-2}+....a_{1}x+a_{0} using the Rational Root Theorem is given as:

\pm (\frac{\textrm{Factors of }a_{0}}{\textrm{Factors of } a_{n}}})

Here, a_{0}=-15,a_{n}=3

Factors of -15 = \pm1,\pm3,\pm5,\pm15

Factors of 3 = \pm1,\pm3

Now, possible roots are given as:

\pm (\frac{\textrm{Factors of }a_{0}}{\textrm{Factors of } a_{n}}})\\\\=\pm(\frac{\pm1,\pm3,\pm5,\pm15}{\pm1,\pm3})\\\\=\pm\frac{1}{1},\pm\frac{1}{3},\pm\frac{3}{1},\pm\frac{3}{3},\pm\frac{5}{1},\pm\frac{5}{3},\pm\frac{15}{1},\pm\frac{15}{3}\\\\=\pm1,\pm\frac{1}{3},\pm3,\pm1,\pm5,\pm\frac{5}{3},\pm15,\pm5\\\\=\pm1,\pm \frac{1}{3},\pm3, \pm 5, \pm \frac{5}{3},\pm15

Therefore, option 1 is correct.

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