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3 years ago

Fill in the missing number to complete the linear equation that gives the rule for this table.

Mathematics

1 answer:

sveta [45]3 years ago

6 0

Y = x + 21
Plug any of the x values in to the equation to confirm.

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Pls help with this thx

Natalija [7]

1. 55
2. N/A - Sorry. I can’t see the numbers properly.
3. 180

4 0

2 years ago

Seth is trying to find the unit price for a package of blank compact discs on sale at 10 for $5.49. Find his mistake and correct

hoa [83]

It is about .55 cents for each disk

3 0

3 years ago

El valor de 2 – 3(5 + 2)(5 – 8) es

Margarita [4]

Answer:

Step-by-step explanation:

2 - 3 ( 5 + 2 ) ( 5 - 8 )

= 2 - 3 ( 7 ) ( -3 )

= 2 + 63

= 65

6 0

2 years ago

Solve the following system of equations. Write each of your answers as a fraction reduced to lowest terms. In other words, write

morpeh [17]

Answer:

x = 57/28

y = -95/84

z = 97/168

Step-by-step explanation:

Use the application in the next link: https://www.zweigmedia.com/RealWorld/tutorialsf1/scriptpivotold.html

Start with the expanded array:

$\left[\begin{array}{cccc}1&5&8&1\\3&2&2&5\\-2&-7&2&5\\\end{array}\right]$

then using the tool provided, make row operations until you find the solution:

r2 = r2-3r1

$\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\-2&-7&2&5\\\end{array}\right]$

r3 = r3+2r1

$\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\0&3&18&7\\\end{array}\right]$

r2 = r2*(-1/13)

$\left[\begin{array}{cccc}1&5&8&1\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]$

r1 = r1- r2*5

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]$

r3 = r3+ r2*-3

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&168/13&97/13\\\end{array}\right]$

r3 = r3*13/168

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&1&97/168\\\end{array}\right]$

r2 = r2- r3*22/13

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]$

r2 = r2+ r3*6/13

$\left[\begin{array}{cccc}1&0&0&57/28\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]$

Here you have a reduced array an therefore the answers to each variable are on each row:

$\left[\begin{array}{c}x\\y\\z\end{array}\right]$

8 0

3 years ago

What is the probability that the card drawn is a diamond and a jack

SpyIntel [72]

Answer:

1/26=4/104

Step-by-step explanation:

The probability of pulling a diamond if completely shuffled properly, is a 1/4. Because there are 4 suits. This is only if, there are no jokers.

And the probability of pulling a jack, is a 4/51. Because there are 4 jacks out of the 51 cards, but you already pulled out a diamond card, so you take 1 out.

Multiply them together, and you will get 4/104 = 1/26

There is a 1/26 chance of pulling out a diamond card, then a jack.

4 0

3 years ago