Answer:
The length of their hair reduces. This is because the length of hair is dependent on the growth phase (anagen phase) of the hair follicles. When one is young, the cells of the papilla divide more rapidly and hence cause the length of the hair to be long before reaching transitional phase (catagen phase) and then shed off in the telogen phase. The older one gets, the papilla cells do not divide as rapidly and the length of the hair shortens with age.
Answer:
Study 1 Answers:
1) 0.76 represents the multiplier of the bacteria, in this case it is decreasing by 24% because the formula for exponential decay is 1 - r.
2) 1290 represents the initial value, or before the study began.
Study 2 Answers:
1) 1180 is the initial value, or before the study began.
2) Study 1 started with more bacteria
3) Study 1 is experiencing exponential decay, while study 2 is experiencing exponential growth
Step-by-step explanation:
Exponential functions are in the form 
, where a is the initial value, b is the multiplier, and x represents inputs, such as hours after a bacteria study.
Any multiplier above 1.00 is experiencing exponential growth, meaning it grows gradually over time, and any multiplier below 1.00 is experiencing exponential decay, meaning it decreases in population over time.
Answer: a 20% chance
Step-by-step explanation:
All you need to do is 2/10 = .2 = 20%
We do this because if 2 chose to read and there are 10 kids.
→ 
8 and 10 can both be divided by 2. So, 8 ÷ 2 is 4 and 10 ÷ 2 is 5.
Hope this helps :)
Answer:
(X) 0 1 2 3 4
P(X) 0.17 0.23 0.27 0.24 0.09
F(x) 0.17 0.04 0.65 0.91 1
Step-by-step explanation:
Given that;
(X) 0 1 2 3 4
P(X) 0.17 0.23 0.27 0.24 0.09
cumulative distribution function can be calculated by; be cumulatively up the value of p(x) with the values before it;
so
x F(x)
0 P(X = 0) = 0.17
1 P(X = 0) + P(X = 1) = 0.17 + 0.23 = 0.4
2 P(X = 0) + P(X = 1) + P(X = 2) = 0.17 + 0.23 + 0.27 = 0.65
3 P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.17 + 0.23 + 0.27 + 0.24 = 0.91
4 P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.17 + 0.23 + 0.27 + 0.24 + 0.09 = 1
Therefore, cumulative distribution function f(x) is;
(X) 0 1 2 3 4
P(X) 0.17 0.23 0.27 0.24 0.09
F(x) 0.17 0.04 0.65 0.91 1
