In this case, we have a colored dot at -1 and a white dot at 3, then the interval notation for that graphed interval will be:
[-1, 3).
<h3>How to write the interval of values in the graph using interval notation?</h3>
First, remember that the symbols ( and ) are used for ends that do not belong to the interval.
For example, if our interval is 1 < x < 2
1 and 2 do not belong to the solution interval, thus, the solution interval is (1, 2).
While [ and ] are used when the ends belong. For example, in:
1 ≤ x ≤ 2
The interval notation is [1, 2]
And in:
1 < x ≤ 2
(1, 2]
And so on.
On the number line, the notation is:
- Colored dot: the point belongs to the interval.
- White dot: the point does not belong to the interval.
In this case, we have a colored dot at -1 and a white dot at 3, then the interval notation for that graphed interval will be:
[-1, 3).
If you want to learn more about interval notation.
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Answer:
Step-by-step explanation:
The general equation is
y = 2.49x + 24.99
The number of cones bought is x
The cake cost is 24.99
The total cost is y
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So the meaning of (5,37.44) is that she bought 5 cones and 1 cake. Let's just check that out.
Check
y = 2.49*5 + 24.99
y = 12.45 + 24.99
y = 37.44
So the total cost (y) of 5 cones (2.49 each) and 1 cake ($24.99) is 37.44
It would be 11.21 percent, hope it helps.
Answer:
a
Step-by-step explanation:
Answer:
The correct figure is B.
Step-by-step explanation:
The statement provided is:
"If it is an equilateral triangle, then it is an isosceles triangle"
The contra-positive of a statement is determined by switching the hypothesis and conclusion of the provided statement and negating both.
Then the contra-positive of the statement provided will be:
- Switching the hypothesis and conclusion:
If it is an isosceles triangle - It is an equilateral triangle.
- Negating both the statements:
If it is not an isosceles triangle - it is not an equilateral triangle.
Thus, the contra-positive of the statement is:
"If it is not an isosceles triangle, then it is not an equilateral triangle."
Thus, the correct figure is B.