Question

Calculate the magnitude of the force between two point charges where q1 = +5.30 ?C and Q2 = +11.2 11C where the separation between the charges is R = 0.22 m. O A. 11.0 Newtons O B. 18.3 Newtons ° C. 27.4 Newtons 0 D. 41.5 Newtons

Answer 1

Answer:

Magnitude of force, F = 11 Newtons

Explanation:

Charge 1, $q_1=5.3\ \mu C=5.3\times 10^{-6}\ C$

Charge 2, $q_2=11.2\ \mu C=11.2\times 10^{-6}\ C$

The separation between the charges is, r = 0.22 m

We have to find the magnitude of the force between two point charges. It can be calculated using the formula as :

$F=k\dfrac{q_1q_2}{r^2}$

$F=9\times 10^9\times \dfrac{5.3\times 10^{-6}\ C\times 11.2\times 10^{-6}\ C}{(0.22\ m)^2}$

F = 11.03 N

or

F = 11 Newtons

Hence, this is the required solution.