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lesantik [10]
4 years ago
11

In an open system, the vapor pressure is equal to the outside air pressure. true false

Physics
2 answers:
Anvisha [2.4K]4 years ago
8 0
False if the pressure is in an open system it could not be equal to the outside

elena-s [515]4 years ago
4 0

Answer:

A) True

Explanation:

Hello! I can assure you that this answer is true.  In an open system, the vapor pressure is equal to the outside air pressure at a liquid's boiling point. Hope this comes to your help! (:

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Answer:

The mass will stay the same throughout time

3 0
3 years ago
Which radioisotope is used in dating geological formations?
ziro4ka [17]
<h2>Answer: U-238</h2>

Explanation:

Let's begin by explaining that for radioactive geological dating (also called radioisotope dating) in which radioactive impurities were selectively incorporated when the fossil materials were formed, it is very useful to compare it with a naturally occurring radioisotope having a known half-life.

Now, taking into account that the <u>fossils are millions and millions of years old, radioisotopes are needed that exceed this measure. </u>

To understand it better:

The longer the half-life of a radioisotope, the greater its utility for estimating fossil ages or geological formations.

In this sense, uranium-238 (U238) has a half-life of 4,470 million years, therefore, it is among the most commonly used radioisotopes for fossil and geological dating.

6 0
3 years ago
A brick moves across a rough surface at constant velocity. Which of the following are forces that should be included in a free b
12345 [234]
But friction is what would make it slow down so...
3 0
4 years ago
A horse running at 3 m/s speeds up with a constant acceleration of 5 m/s2. How fast is the
Elan Coil [88]

Answer:

The horse is going at 12.72 m/s speed.

Explanation:

The initial speed of the horse (u) = 3 m/s

The acceleration of the horse (a)= 5 m/s^{2}

The displacement( it is assumed it is moving in a straight line)(s)= 15.3 m

Applying the second equation of motion to find out the time,

s=ut+\frac{1}{2}at^{2}

15.3=3t+2.5t^{2}

2.5t^{2}+3t-15.3=0

Solving this quadratic equation, we get time(t)=1.945 s, the other negative time is neglected.

Now applying first equation of motion, to find out the final velocity,

v=u+at

v=3+1.945*5

v=3+9.72

v=12.72 m/s

The horse travels at a speed of 12.72 m/s after covering the given distance.

7 0
4 years ago
A kangaroo jumps up with an initial velocity of
ycow [4]

Answer:

2.3

Explanation:

4 0
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