So,
1. Tawni swam a 50-m Freestyle in 40.8 secs.
2. Pepita swam a 100-m Butterfly in 60.2 secs.
3. Susana swam a 200-m Medley in 112.4 secs.
Manipulate the distances so that they are the same.
Tawni would swim a 200-m in 163.2 secs.
Pepita would swim a 200-m in 120.4 secs.
Susana woulld swim a 200-m in 112.4 secs.
Susana swam the fastest.
Answer:
me too
Step-by-step explanation:
Answer:
Translating to the question, the toy's value as a function of time is
![t = ab^{w}](https://tex.z-dn.net/?f=t%20%3D%20ab%5E%7Bw%7D)
To determine constants a and b, we use points given by graph.
First, (0,5) to find a:
![5= a.b^{0}](https://tex.z-dn.net/?f=5%3D%20a.b%5E%7B0%7D)
a = 5
Now, (3,10) to determine b:
![10=5b^{3}](https://tex.z-dn.net/?f=10%3D5b%5E%7B3%7D)
![b=\sqrt[3]{2}](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B3%5D%7B2%7D)
b = 1.26
The toy's value as a function of time in weeks is t = ![5.(1.26)^{w}](https://tex.z-dn.net/?f=5.%281.26%29%5E%7Bw%7D)
Step-by-step explanation:
If the plane is flying at an altitude of 21,000 feet, it is perpendicular to the observer's horizontal line of sight. Thus, I concluded that the given information be assigned to the attachment below.
Given -
( Observer at point O, plane flying at point P
( Plane at 55° angle to horizontal line of sight, altitude of 21,000 feet
The distance ( x ), is represented by the line segment OP, with which we have to determine the length of. Therefore we can conclude the following -
![Sin( 55 ) = Altitude / Distance,\\Sin( 55 ) = 21,000 / x,\\----------------\\x = \frac{21,000}{Sin( 55 )},\\x = 21,000 / 0.81915204428\\\\x = ( About ) 25636 feet\\](https://tex.z-dn.net/?f=Sin%28%2055%20%29%20%3D%20Altitude%20%2F%20Distance%2C%5C%5CSin%28%2055%20%29%20%3D%2021%2C000%20%2F%20x%2C%5C%5C----------------%5C%5Cx%20%3D%20%5Cfrac%7B21%2C000%7D%7BSin%28%2055%20%29%7D%2C%5C%5Cx%20%3D%2021%2C000%20%2F%200.81915204428%5C%5C%5C%5Cx%20%3D%20%28%20About%20%29%2025636%20feet%5C%5C)
<u><em>As you can see, the distance from the plane to the observer is about 25,636 ft!</em></u>