Answer:
b = 7/2
x = 11/2
y = 21/2
z = -4
Step-by-step explanation:
2x + 2y + 2z = 24
x + y + z = 12
b + 2x + y + z = 21
2b + 2y = 28
b + y = 14
3x + y + z = 23
we can start anywhere by transforming these equations in a way that always one variable is excised by others.
so, e.g.
b = 14 - y
14 - y + 2x + y + z = 21
2x + z = 7
z = 7 - 2x
3x + y + 7 - 2x = 23
x + y = 16
16 + z = 12
z = -4
-4 = 7 - 2x
-11 = -2x
11 = 2x
x = 11/2
11/2 + y = 16
y = 16 - 11/2 = 32/2 - 11/2 = 21/2
b = 14 - 21/2 = 28/2 - 21/2 = 7/2
Answer:
77x+33y
Step-by-step explanation:
Eliminate redundant parentheses
(33x+53y)+(44x−20y)
33+53+44−20
Combine like terms
33x+53y+44x−20y
77+53−20
Combine like terms
77x+53y−20y
77+33
Solution:
77+33
Answer:
The answer should be 2A/(a+b)=h
Answer: 540
Step-by-step explanation:
Given : The owner of a stereo store wants to advertise that he has many different sound systems in stock.
Number of different CD players =6
Number of different receivers= 10
Number of different speakers = 9
We are assuming that a sound system consists of one of each .
Then by Fundamental principle of counting , we have
The number of different sound systems can he advertise = (Number of different CD players)x (Number of different receivers) x(Number of different speakers)
= 6 x10 x 9 =540
Hence, the number of different sound systems can he advertise =540
Step-by-step explanation:
(a + b)² = 9
(b + c)² = 25
(a + c)² = 81
Taking the square root:
a + b = ±3
b + c = ±5
a + c = ±9
By adding these three equations together and dividing both sides by 2, we get the value of a + b + c.
Possible combinations for a + b + c such that the sum is greater than or equal to 1 are:
a + b + c = (-3 + 5 + 9)/2 = 11/2
a + b + c = (3 − 5 + 9)/2 = 7/2
a + b + c = (3 + 5 + 9)/2 = 17/2
