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tino4ka555 [31]
3 years ago
13

Let X = the time (in 10−1 weeks) from shipment of a defective product until the customer returns the product. Suppose that the m

inimum return time is γ = 3.5 and that the excess X − 3.5 over the minimum has a Weibull distribution with parameters α = 2 and β = 1.5.
(a) What is the cdf of X?
F(x) = 0 x < 3.5
1−e^−((x−3.5)2.5​)2 x ≥ 3.5
(b) What are the expected return time and variance of return time? [Hint: First obtain
E(X − 3.5)
and
V(X − 3.5).]
(Round your answers to three decimal places.)

E(X) = 10^−1 weeks
V(X) = (10^−1 weeks)2

(c) Compute
P(X > 6).
(Round your answer to four decimal places.)

Mathematics
1 answer:
Aleks [24]3 years ago
5 0

Answer:

Step-by-step explanation: see attachment for solution

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9 × ( 5 + 2 ) = ( 9 × _ ) + ( 9 × _ )???
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3 years ago
A camera shop purchases a camera for $56.98 and sells it for $102.56. What is the percent of markup?
Amiraneli [1.4K]

Answer:

180%

Step-by-step explanation:

Set up an equation:

Variable x = percent of markup

102.56/56.98 = x/100

Cross multiply

102.56 × 100 = 56.98 × x

10,256 = 56.98x

Divide both sides by 56.98:

179.99297.... = x

Round to nearest whole number:

180 = x

Check your work:

56.98 × 180%

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56.98 × 1.80

102.564

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102.56

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8 0
3 years ago
Scores of an IQ test have a​ bell-shaped distribution with a mean of 100 and a standard deviation of 13. Use the empirical rule
Yuri [45]

Answer:

(a) 68% of people has an IQ score between 87 and 113​.

(b) 5% of people has an IQ score less than 74 or greater than 126.

(c) 0.15% of people has an IQ score greater than 139​.

Step-by-step explanation:

Given information:Scores of an IQ test have a​ bell-shaped distribution,

mean = 100

standard deviation = 13

According to the empirical rule

68% data lies between \overline{x}-\sigma and \overline{x}+\sigma.

95% data lies between \overline{x}-2\sigma and \overline{x}+2\sigma.

99.7% data lies between \overline{x}-3\sigma and \overline{x}+3\sigma.

(a)

\overline{x}-\sigma=100-13=87

\overline{x}+\sigma=100+13=113

[\overline{x}-\sigma,\overline{x}+\sigma]=[87,113]

Using empirical rule we can say that 68% of people has an IQ score between 87 and 113​.

(b)

\overline{x}-2\sigma=100-2(13)=74

\overline{x}+2\sigma=100+2(13)=126

[\overline{x}-2\sigma,\overline{x}+2\sigma]=[74,126]

Using empirical rule we can say that 95% of people has an IQ score between 74 and 126​.

The percentage of people has an IQ score less than 74 or greater than 126 is

P = 1- percent of people has an IQ score between 74 and 126​.

P = 1- 95%

P = 5%

Therefore 5% of people has an IQ score less than 74 or greater than 126.

(c)

\overline{x}-3\sigma=100-3(13)=61

\overline{x}+3\sigma=100+3(13)=139

[\overline{x}-3\sigma,\overline{x}+3\sigma]=[61,139]

Using empirical rule we can say that 99.7% of people has an IQ score between 61 and 139​.

The percentage of people has an IQ score less than 61 or greater than 139 is

P = 1- percent of people has an IQ score between 61 and 139​.

P = 1- 99.7%

P = 0.3%

The percentage of people has an IQ score greater than 139​ is

P=\frac{1}{2}(0.3\%)=0.15\%

Therefore 0.15% of people has an IQ score greater than 139​.

5 0
4 years ago
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