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tino4ka555 [31]
2 years ago
13

Let X = the time (in 10−1 weeks) from shipment of a defective product until the customer returns the product. Suppose that the m

inimum return time is γ = 3.5 and that the excess X − 3.5 over the minimum has a Weibull distribution with parameters α = 2 and β = 1.5.
(a) What is the cdf of X?
F(x) = 0 x < 3.5
1−e^−((x−3.5)2.5​)2 x ≥ 3.5
(b) What are the expected return time and variance of return time? [Hint: First obtain
E(X − 3.5)
and
V(X − 3.5).]
(Round your answers to three decimal places.)

E(X) = 10^−1 weeks
V(X) = (10^−1 weeks)2

(c) Compute
P(X > 6).
(Round your answer to four decimal places.)

Mathematics
1 answer:
Aleks [24]2 years ago
5 0

Answer:

Step-by-step explanation: see attachment for solution

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3 years ago
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Answer:

a = -15, b = -.5, c = -1

Step-by-step explanation:

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I need help on these 2 questions. Algebra 1
hammer [34]

Answer:

7. is G

8. f(4)=-120

Step-by-step explanation:

7. les do f(0)=4 since its the easiest

F. f(0)=0.4(0+5)(0-2)

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G. f(0)=-0.4(0+5)(0-2)

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H. f(0)=-0.4(0-5)(0+2)

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so G n H

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5 0
3 years ago
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