Question

Trigonometry- can someone help me please? (this was all I was given)

Answer 1

$sinX = \dfrac{ \sqrt{119} }{12}$

$CosX = \dfrac{5}{12}$

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Ratio :
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Sin X : Cos X

$\dfrac{ \sqrt{119} }{12} : \dfrac{5}{12}$

$\sqrt{119} : 5$

$(\sqrt{119})^2 : (5)^2$

$119 : 25$