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Reil [10]
3 years ago
15

Can someone please help with these 4 questions?

Mathematics
1 answer:
choli [55]3 years ago
7 0

Answer:

Q4. 2144     Q5. -16     Q6.   Downwards     Q7.   0 seconds

Step-by-step explanation:

Q4.    h(t) = -16t² + 2400    Substitute 4 for t

h(4) = -16(4)² + 2400          Simplify the exponent

h(4) = -16(16) + 2400          Multiply

h(4) = -256 + 2400            Add

h(4) = 2144

Q5.   I graphed the equation on the graph below to find the instantaneous velocity. The instantaneous velocity is -16.

Q6.   At 4.5 seconds, the water rocket is traveling down because the highest point the rocket goes is at 2.8, so 4.5 is traveling downwards.

Q7.   0 seconds because the rocket goes 0 feet in 0 seconds.

If these answers are correct, please make me Brainliest!

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this week Shauna practiced her saxophone for 25 minutes less than 3 times the number of minutes she practiced last week. if she
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Answer:

3m - 25

Step-by-step explanation:

3m - 25 will represent how many minutes she practiced this week:

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4 years ago
6 to the 4th power times 6 to the 4th power
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1679616.

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Square Roots
dlinn [17]
4 is the square root of 16

i think that what you are asking, but if it is not tell me and i can try to help more :)
4 0
4 years ago
Find the critical points, domain endpoints, and local extreme values for the function
aliina [53]

Answer:

a) x = -3, b) x = 0, x = -6, c) x = 0, d) x = -6

Step-by-step explanation:

a) Let derive the function:

f'(x) = \frac{10\cdot x \cdot (x+3)-5\cdot x^{2}}{25\cdot (x+3)^{2}}

f'(x) is undefined when denominator equates to zero. The critical point is:

x = -3

b) f'(x) = 0 when numerator equates to zero. That is:

10\cdot x \cdot (x+3) - 5\cdot x^{2} = 0

10\cdot x^{2}+30\cdot x -5\cdot x^{2} = 0

5\cdot x^{2} + 30\cdot x = 0

5\cdot x \cdot (x+6) = 0

This equation shows two critical points:

x = 0, x = -6

c) The critical points found in point b) and the existence of a discontinuity in point a) lead to the conclusion of the existence local minima and maxima. By plotting the function, it is evident that x = 0 corresponds to a local maximum. (See Attachment)

d) By plotting the function, it is evident that x = -6 corresponds to a local minimum. (See Attachment)

8 0
3 years ago
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