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IRINA_888 [86]
3 years ago
7

What is the answer to 4x - 16

Chemistry
2 answers:
evablogger [386]3 years ago
5 0

Answer:-64

Explanation:

andrezito [222]3 years ago
4 0
It simply equals 4x-16.......
the expression is in lowest terms, so you can’t do anything else
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How many grams of bromine are required to react completely with 37.4 grams aluminum chloride?
Gekata [30.6K]

Answer:

None  

Explanation:

Cl₂ is above Br₂ in the activity series.

Bromine will not displace chlorine from its salts.

The reaction will not occur.

8 0
2 years ago
Read 2 more answers
Which model of the atom was used as a result of JJ Thomson's cathode ray
mariarad [96]

Answer:

a. Plum pudding model

Explanation:

The plum pudding model of the atom was proposed by J.J. Thomson. It was the model he derived from his experiment on the gas discharge tube.

J.J Thomson was the first person to discover electrons which he called cathode rays because in the discharge tube, they emanate from the cathode.

  • This led him to suggest the plum pudding model of the atom.
  • The model reflects electrons being surrounded by a volume of negative charges.
6 0
3 years ago
How many nuclei of 238 92 U 92 238 U remain in a rock if the activity registers 290 decays per second?(Note that the half life o
Rom4ik [11]

Answer:

Use the activity formula,  

T1/2 = 4.468 x 10^9 yr x 365 x 24 x 3600 = 1.409 x 10^17 sec  

l = ln(2)/T1/2 = ln(2)/1.409 x 10^17 = 4.91932697 x 10^-18 s-1  

DN/Dt = lN, 265 = 4.91932697 x 10^-18 x N  

<u><em>N = 5.38 x 10^19 nuclei</em></u>

7 0
3 years ago
How many grams of NH3 can be produced from 12.0g of H2?
RSB [31]

Answer:

Balanced reaction:

3 H2 (g)  + N2 (g)  → 2 NH3 (g)

Use stoichiometry to convert g of H2 to g of NH3.  The process would be:

g H2 → mol H2 → mol NH3 → g NH3

12.0 g H2 x (1 mol H2 / 2.02 g H2) x (2 mol NH3 / 3 mol H2) x (17.03 g NH3 / 1 mol NH3) = 67.4 g NH3

Explanation: See above

Hope this helps, friend.

8 0
2 years ago
Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3 (g). At equilibrium, th
artcher [175]

Answer:

The <u>equilibrium constant</u> is:

              k_c=0.0030M^{-2}

Explanation:

The correct equation is:

  •   N₂(g)    +    3H₂(g)    ⇄    2NH₃(g)

Thus, with the equilibrium concentrations you can calculate the equilibrium constant, Kc.

The equation for the equilibrium constant is:

         k_c=\dfrac{[NH_3]^2}{[N_2]\cdot [H_2]^3}

Substituting:

        k_c=\dfrac{(0.105M)^2}{(1.1M)\cdot (1.50M)^3}

         k_c=0.0030M^{-2}

6 0
3 years ago
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