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mr Goodwill [35]
3 years ago
14

The temperature of a container of oxygen gas is increased from 149 k to 298 k which of the following statement is true

Chemistry
1 answer:
ozzi3 years ago
8 0

Answer:

______is used in production of hard disk.

Explanation:

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The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 genera
nevsk [136]

Answer:

The volume of carbon dioxide gas generated 468 mL.

Explanation:

The percent by mass of bicarbonate in a certain Alka-Seltzer = 32.5%

Mass of tablet = 3.45 g

Mass of bicarbonate =3.45 g\times \frac{32.5}{100}=1.121 mol

Moles of bicarbonate ion = \frac{1.121 g/mol}{61 g/mol}=0.01840 mol

HCO_3^{-}(aq)+HCl(aq)\rightarrow H_2O(l)+CO_2(g)+Cl^-(aq)

According to reaction, 1 mole of bicarbonate ion gives with 1 mole of carbon dioxide gas , then 0.01840 mole of bicarbonate ion will give:

\frac{1}{1}\times 0.01840 mol=0.01840 mol of carbon dioxide gas

Moles of carbon dioxide gas  n = 0.01840 mol

Pressure of the carbon dioxide gas = P = 1.00 atm

Temperature of the carbon dioxide gas = T = 37°C = 37+273 K=310 K

Volume of the carbon dioxide gas = V

PV=nRT (ideal gas equation)

V=\frac{nRT}{P}=\frac{0.01840 mol\times 0.0821 atm L/mol K\times 310 K}{1.00 atm}=0.468 L

1 L = 1000 mL

0.468 L =0.468 × 1000 mL = 468 mL

The volume of carbon dioxide gas generated 468 mL.

5 0
3 years ago
Identify the catalyst in this reaction, explain how
telo118 [61]

Question:

Sulfuric acid was once produced through the reaction of sulfur trioxide with water. Sulfur trioxide can form through the reaction of sulfur dioxide and oxygen gas. When nitrogen monoxide gas is added to the system, the reaction speeds up significantly because it proceeds through the following steps:

equations

Identify the catalyst in this reaction, explain how you know it is the catalyst, and describe how it increases the rate of the reaction.

Answer:

NO

It is present but not consumed

NO Lowers the activation energy of the reaction

Explanation:

A catalyst is a substance that is present in a chemical reaction and enables the reaction to occur at a faster rte but does not take part n the reaction

Therefore, whereby NO is not consumed, it is the catalyst

It functions by lowering the activation energy

5 0
3 years ago
You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute b
alexdok [17]

Answer:

             0.045 L  or 45 mL

Explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

Moles = 0.09 moles

Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L

8 0
2 years ago
Ar (g) is placed in a 3.80 L container at 320 K. The gas pressure is 0.496 atm.
nata0808 [166]

Answer:

PV=nRt

Therefore n(number of moles)=PV/RT

=>(0.49×3.80)/(0.08206×320)

Therefore Number of moles is = 0.071mols

Explanation: By using the Real gas equation..

PV=NRT .

We can solve for the number of moles of Ar by making N the subject..

Always make sure you pressure is In atm, your Volume is in Litres and temperature in degree Kelvin.

Also Recall the universal gas constant R used in this type of questions which is 0.08206.

Hence l, by making N the subject we get our answer as

3 0
3 years ago
If 26.2 mL of AgNO3 is needed to precipitate all the Cl− ions in a 0.785-mg sample of KCl (forming AgCl), what is the molarity o
sweet-ann [11.9K]

<u>Answer:</u>

<em>The molarity of the AgNO_3 solution is 4.02 \times 10^4 M </em>

<em></em>

<u>Explanation:</u>

The Balanced chemical equation is

1AgNO_3 (aq) +1KCl (aq) > 1 AgCl (s)+1KNO_3 (aq)

Mole ratio of AgNO_3 : KCl is 1 : 1

So moles AgNO_3  = moles KCl

Moles KCl = \frac {mass}{molarmass}

= \frac {0.785 mg}{(39.1+35.5 g per mol)}

= \frac {0.000785 g}{74.6 g  per mol}

= 0. 0000105 mol KCl

= 0.0000105 mol AgNO_3

So  Molarity

= \frac {moles of solute}{(volume of solution in L)}

= \frac {0.0000105 mol}{26.2 mL}

=\frac {0.0000105 mol}{0.0262 L}

= 0.000402M or mol/L is the Answer

(Or) 4.02 \times 10^4 M is the Answer

6 0
2 years ago
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