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3 years ago

How do polar molecules respond when they are placed between two metal plates, one positively charged and one negatively charged?

2 answers:

6 0

A polar molecule will have a partially positively charged end and a partially negatively charged end. The negatively charged end of the polar molecule will get attracted to the positively charged metal plate and the positively charged end of the polar molecule will get attracted to the negatively charged metal plate. This is based on Coulomb’s law of attraction of opposite charges.

kakasveta [241]3 years ago

5 0

Gradpoint

The molecules align to the electric field

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Nitric oxide is formed in automobile exhaust when nitrogen and oxygen in air react at high temperatures.N2(g) + O2(g) 2NO(g)The

yanalaym [24]

Answer : The correct option is, (E) 7.8 atm

Explanation :

The partial pressure of $N_2$ = 8.00 atm

The partial pressure of $O_2$ = 5.00 atm

$K_p$ = 0.0025

The balanced equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

Initial pressure 8.00 5.00 0

At eqm. (8.00-x) (5.00-x) 2x

The expression of equilibrium constant $K_p$ for the reaction will be:

$K_p=\frac{(p_{NO})^2}{(p_{N_2})(p_{O_2})}$

Now put all the values in this expression, we get :

$0.0025=\frac{(2x)^2}{(8.00-x)\times (5.00-x)}$

By solving the terms, we get:

$x=0.15atm$

The equilibrium partial pressure of $N_2$ = (8.00 - x) = (8.00 - 0.15) = 7.8 atm

Therefore, the equilibrium partial pressure of $N_2$ is 7.8 atm.

3 0

3 years ago

What is the pH of this solution?

Vesnalui [34]

Answer:

pH = 11.216.

Explanation:

Hello there!

In this case, according to the ionization of ammonia in aqueous solution:

$NH_3+H_2O\rightleftharpoons NH_4^++OH^-$

We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:

$Kb=\frac{[NH_4^+][OH^-]}{[NH_3]} \\\\1.80x10^{-5}=\frac{x*x}{0.150-x}$

However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:

$1.80x10^{-5}=\frac{x*x}{0.150}\\\\x=\sqrt{1.80x10^{-5}*0.150}=1.643x10^{-3}M$

Which is also:

$[OH^-]=1.643x10^{-3}M$

Thereafter we can compute the pOH first:

$pOH=-log(1.643x10^{-3}M)\\\\pOH=2.784$

Finally, the pH turns out:

$pH=14-2.784\\\\pH=11.216$

Regards!

5 0

2 years ago

Briefly discuss the 3 most important properties of metals

Elan Coil [88]

Answer: Luster: Metals are shiny when cut, scratched, or polished.

Malleability: Metals are strong but malleable, which means that they can be easily bent or shaped.

Conductivity: Metals are excellent conductors of electricity and heat.

Explanation: Hope this helped!

7 0

2 years ago

Calculate the moles and grams of solute in 2.0 L of 0.30M Na SO..

Ostrovityanka [42]

Answer:

Number of moles of solute = 0.6 mole

Mass =13.8 g

Explanation:

Given data:

Number of moles of sodium = ?

Volume = 2.0 L

Molarity = 0.30 M

Mass in gram of sodium= ?

Solution:

<em>Number of moles:</em>

Molarity = number of moles of solute / volume in litter

Number of moles of solute = Molarity × volume in litter

Number of moles of solute = 0.30 M × 2.0 L

Number of moles of solute = 0.6 mole

Mass = Number of moles × molar mass

Mass = 0.6 mole× 23 g/mol

Mass =13.8 g

3 0

2 years ago

What do we call the study of matter and how matter changes?

svet-max [94.6K]

Answer:

Explanation:

Chemistry is the study of matter and the changes that matter undergoes. Matter is anything that has mass and takes up space.

7 0

2 years ago