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alexandr1967 [171]
3 years ago
15

How does an iron nail become a magnet when it is placed in a strong magnetic field

Physics
2 answers:
lord [1]3 years ago
5 0
Metals, especially iron, have this form of electron cloud around it. When it's placed in a magnetic field these electrons line up
allsm [11]3 years ago
4 0

Explanation:

A current flowing in a wire creates a magnetic field around the wire.

This concept is used in an electromagnet.

Wrap a wire around the iron nail and turned into a coil and then connect it to a battery. This system is called an electromagnet.

By adding the more turns to the coil or increasing the current in the coil, you can make an electromagnet more stronger.

Iron is used in an electromagnet as it easily gain magnetic properties. When the current is flowing in the coil then it will be easily gain magnetic properties and when the current is stopped then it will loose magnetic properties.

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A vessel is filled with a liquid of density 1900 kg/m3 . There are two holes (one above the other) in the side of the vessel. Li
FromTheMoon [43]

Answer:

110 meters is the distance where they will intersect

Explanation:

given,

liquid density = 1900 kg/m³

distance of upper hole = 19 m

distance of lower hole = 117 m

acceleration due to gravity  = 9.8 m/s²

the speed at each point

v = \sqrt{2gh}  

for upper hole  v = \sqrt{2\times 9.8 \times 19}  

                         v  = 19.29 m/s

lower hole    v = \sqrt{2\times 9.8 \times 117}  

                          v = 47.88 m/s

The path for each is parabolic

x = v t

y = \dfrac{1}{2}gt^2  

y = \dfrac{1}{2}g(\dfrac{x}{v})^2  

y = \dfrac{gx^2}{2v^2}  

we get

upper hole

y = \dfrac{9.8\times x^2}{2\times 19.29^2}= 0.0132 x^2  lower hole

y= \dfrac{9.8\times x^2}{2\times 47.88^2}=0.00214x^2  y for upper hole = 80 + y for lower hole

0.0132 x^2= 98 + 0.00214 x^2

0.0082 x^2 = 98

x = 109.32 meters

110 meters is the distance where they will intersect

4 0
3 years ago
What do you expect the enclosed current is for a bar magnet?
BartSMP [9]
The point P lies at a linear distance 1 m from the corner. Magnetic field due to current in wire Magnetic field due to current in wire. Applying Right hand thumb rule, the magnetic field at P is perpendicular to xy plane and into the plane of drawing (i.e. negative z-direction).
6 0
3 years ago
An inductor is connected to an AC power supply having a maximum output voltage of 3.00 V at a frequency of 280 Hz. What inductan
Sergio [31]

Answer:

L = 0.48 H

Explanation:

let L be the inductance, Irms be the rms current, Vrms be the rms voltage and Vmax  be the maximum voltage and XL be the be the reactance of the inductor.

Vrms = Vmax/(√2)

         = (3.00)/(√2)

         = 2.121 V

then:

XL = Vrms/I  

     = (2.121)/(2.50×10^-3)

     = 848.528 V/A

that is L = XL/(2×π×f)

              = (848.528)/(2×π×(280))

              = 0.482 H

Therefore, the inductance needed to kepp the rms current less than 2.50mA is 0.482 H.

6 0
3 years ago
A food refrigerator is to provide a 15,000 kj/h cooling effect while rejecting 22,000 kj/h of heat. calculate the cop of this re
svp [43]
Coefficient of performance or more commonly known as COP is calculated through the equation,
                                 COP = ((T₂)/(T₂ - T₁)) 
where T₂ is the hot temperature and T₁ is the cold temperature. Similarly, these can also be,
                      COP = heat ejected / (heat ejected - heat provided)
 Substituting,
                     COP = 22,000 / (22,000 - 15,000) = 3.14
Thus, the value of the COP is approximately 3.14. 
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