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mash [69]
3 years ago
8

Why do place on earth receives different amounts of sunlight

Physics
2 answers:
Tatiana [17]3 years ago
8 0

Answer:

Different parts of Earth's surface receive different amounts of sunlight. ... Because of the Earth's tilt the sun's rays strike the surface at a slant at the poles; they are less focused. This spreads the rays over a wide area. Because the sun's rays hit at a slant, the area is heated less.

Explanation:

From Google

Can I have brainliest

Pachacha [2.7K]3 years ago
3 0

Answer:

Because of earth's tilt

Explanation:

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n astronaut who weighs 800 N on the surface of the earth lifts off from planet Zuton in a space ship. The free-fall acceleration
ANTONII [103]

Answer: 0.29 kN

Explanation:

We have the following data:

W_{E}=800 N is the weight of the astronaut on Earth

g_{E}=9.8 m/s^{2} is the free fall acceleration due gravity on Earth (directed downwards)

g_{Z}=3 m/s^{2} is the free fall acceleration due gravity on Zuton (directed downwards)

a=0.5 m/s^{2} is the acceleration of the spaceship at litoff (directed upwards)

We have to find the <u>magnitude of the force</u> F the space ship exerts on the astronaut.

Firstly, we have to know weight has a direct relation with the mass and the acceleration due gravity. In the case of Earth is:

W_{E}=mg_{E} (1)

Where m is the mass of the atronaut.

Isolating m:

m=\frac{W_{E}}{g_{E}} (2)

m=\frac{800 N}{9.8 m/s^{2}} (3)

m=81.63 kg (4)

Now that we know the mass of the astronaut, we can find its weight on Zuton:

W_{Z}=mg_{Z} (5)

W_{Z}=(81.63 kg)(3 m/s^{2}) (6)

W_{Z}=244.89 N (7)

Then, we can calculate the force the space ship exerts on the astronaut by the following equation:

F-W_{Z}=m.a (8)

Isolating F:

F=m.a+W_{Z} (9)

F=(81.63 kg)(0.5 m/s^{2})+244.89 N (10)

F=285.7 N \frac{1 kN}{1000 N}=0.285 kN (11)

Finally:

F=0.285 kN \approx 0.29 kN

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4 years ago
What are differences between an entrepreneur and an employee<br>​
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Employees execute tasks while entrepreneurs plan. An employee can take work day by day, whereas an entrepreneur has to consider how well the tasks are being performed relative to the long-term plan for the business.
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2 years ago
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A car travelling at 5.0 m/s starts to speed up. After 3.0 s its velocity has increased to 11 m/s. a) What is its acceleration? (
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initially, the car is traveling at 5.0 m/s.

so, we know acceleration for changing velocity is :

a = (v-v_{o})/t ..........(i)

where v is the final velocity

v_{o} is the initial velocity

t is the time taken to change velocity

Now, as per the question :

initial velocity, v_{o}=5.0 m/s

final velocity, v =11 m/s

time taken, t = 3 s

putting the values in equation (i),

a = ( 11-5 )/3

a = 2 m/s²

Therefore, a, after 3 s, is  <em>2 m/s².</em>

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How do clouds become stars ?
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3 0
3 years ago
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Please help. It’s probably easy
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I believe it’s 60km/h

I divided the total distance (120 km) by the time it took to get there (2h) to get this.
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