To calculate the gravitational force acting on an object given the mass and the acceleration due to gravity, use the following formula.
Fg = m • g
Fg = 1.3 kg • 9.8 m/s^2
Fg = 12.74 N or about 12.7 N.
The solution is C. 12.7 N.
Answer:
T₂ = 123.9 N, θ = 66.2º
Explanation:
To solve this exercise we use the law of equilibrium, since the diaphragm does not appear, let's use the adjoint to see the forces in the system.
The tension T1 = 100 N, we create a reference frame centered on the pole
X axis
T₁ₓ -
= 0
T_{2x}= T₁ₓ
Y axis y
T_{1y} + T_{2y} - 200N = 0
T_{2y} = 200 -T_{1y}
let's use trigonometry to find the component of the stresses
sin 60 = T_{1y} / T₁
cos 60 = t₁ₓ / T₁
T_{1y} = T₁ sin 60
T1x = T₁ cos 60
T_{1y}y = 100 sin 60 = 86.6 N
T₁ₓ = 100 cos 60 = 50 N
for voltage 2 it is done in the same way
T_{2y} = T₂ sin θ
T₂ₓ = T₂ cos θ
we substitute
T₂ sin θ= 200 - 86.6 = 113.4
T₂ cos θ = 50 (1)
to solve the system we divide the two equations
tan θ = 113.4 / 50
θ = tan⁻¹ 2,268
θ = 66.2º
we caption in equation 1
T₂ cos 66.2 = 50
T₂ = 50 / cos 66.2
T₂ = 123.9 N
The order of magnitude of my age in seconds is 10^9. I think you'll find that this is true for anyone who is 32 or older.
Answer:
gas is dioatomic
T_f = 330.0 K

Explanation:
Part 1
below equation is used to determine the type Gas by determining
value

where V_i and V_f is initial and final volume respectively
and P_i and P_f are initial and final pressure


\gamma = 1.38
therefore gas is dioatomic
Part 2
final temperature in adiabatic process is given as
](https://tex.z-dn.net/?f=T_f%20%3D%20T_i%2A%5B%5Cfrac%7Bv_i%7D%7BV_f%7D%5D%28%5E%5Cgamma-1%29)
substituing value to get final temperature
![T_f = 260*[\frac{151}{80.6}]^ {(1.38-1)}](https://tex.z-dn.net/?f=T_f%20%3D%20260%2A%5B%5Cfrac%7B151%7D%7B80.6%7D%5D%5E%20%7B%281.38-1%29%7D)
T_f = 330.0 K
Part 3
determine number of moles by using following formula


