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3 years ago

Can somebody please help me

Mathematics

2 answers:

Marysya12 [62]3 years ago

7 0

Answer:

V = 201 ft^3

Step-by-step explanation:

$v = \pi {r}^{2} \times h \\ v = 3.14 \times {2}^{2} \times 16 \\ v = 200.96 \\ v = 201 \: \: {ft}^{3}$

I hope that is useful for you :)

MaRussiya [10]3 years ago

3 0

Answer:

201.06

Step-by-step explanation:

The volume of a cylinder is the area of the base ( $\pi 2^2$ ) times the height (16).

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The ratio of kids to adults in a dollar store is 2:1. Suppose there is a total of 50 kids to adults. How many kids are there?

Taya2010 [7]

The correct answer is 71 kids

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3 years ago

La medida de cada ángulo interno de un polígono regular es 162º. Hallar el número de lados.

Romashka-Z-Leto [24]

Answer:

n = 20

Step-by-step explanation:

[ 180° ( n - 2 ) ] / n = 162°

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2 years ago

What is the perimeter , in feet , of the polygon 15,22,10,18,14,5,5,16

Alinara [238K]

You just add all the sides together for perimeter
the answer is105

5 0

3 years ago

Solve for [x]. The polygons in each 2x-20 16 16 8

Nataly_w [17]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:x = 16$

____________________________________

$\large \tt Solution \: :$

If two polygons are similar, their corresponding sides ratios will be equal to each other.

$\qquad \tt \rightarrow \: \cfrac{8}{16} = \cfrac{2x - 20}{24}$

$\qquad \tt \rightarrow \: \cfrac{1}{2} = \cfrac{2x - 20}{24}$

$\qquad \tt \rightarrow \: 2x - 20 = \cfrac{24}{2}$

$\qquad \tt \rightarrow \: 2x = 12 + 20$

$\qquad \tt \rightarrow \: 2x = 32$

$\qquad \tt \rightarrow \: x = 16$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

7 0

2 years ago

Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0

1 year ago