Another name for them are called groups or families.
AlCl₃
Remember, you want to make their charges cancel. So, we need 3 chlorine atoms (because chlorine has a charge of -1) for every 1 aluminum atom (because aluminum has a charge of +3 ).
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Answer:</h3>
Pb₃O₄ + 4HNO₃ → 2Pb(NO₃)₂ + PbO₂ + 2H₂O
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Explanation:</h3>
- Balancing a chemical equation involves putting appropriate coefficients on the reactants and products to make the number of atoms of each element involved equal on both sides of the equation.
- When a chemical equation is balanced then it obeys the law of conservation of mass.
- The law of conservation of mass requires the mass of reactants to be equal to the mass of the products.
- In this case, to balance the equation, we put the coefficients 1, 4, 2, 1 and 2 receptively on the equation.
Thus, the balanced equation will be;
Pb₃O₄ + 4HNO₃ → 2Pb(NO₃)₂ + PbO₂ + 2H₂O\
- Therefore, on the reactants side there are 3 Pb atoms, 16 O atoms, 4 H atoms and 4 nitrogen atoms.
- Product side : 3 Pb atoms, 16 O atoms, 4 H atoms and 4 nitrogen atoms.
Thus, the equation obeys the law of conservation of mass.
Answer:
3.26×10⁵m³
Explanation:
Given data:
Initial volume = 3.5×10⁵ m³
Initial temperature = 27 °C (27+273= 300 K)
Initial pressure = 101 Kpa
Final volume = ?
Final temperature = -10°C (-10+273 = 263 K)
Final pressure = 95 Kpa
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 101 Kpa × 3.5×10⁵ m³× 263 K / 300 K × 95 Kpa
V₂ = 92970.5 ×10⁵kpa. m³. K / 28500 K.Kpa
V₂ = 3.26×10⁵m³