<span>A. Mechanic agitations</span>
Moles of nitrogen = 49.84 / 28 = 1.78
Moles of hydrogen = 10.7 / 2 = 5.35
Molar ratio of nitrogen to hydrogen = 1 : 3
Hydrogen required = 1.78 x 3 = 5.34
Therefore, hydrogen is in excess and nitrogen is the limiting reagent.
The amount of water that could we get if you started with 250.0 grams of hydrogen is 2,250 grams.
<h3>What is moles - mass realation?</h3>
Moles (n) and mass of any substance are related to each other according to the given equation as:
n = W/M, where
W = given mass
M = molar mass
Given balanced chemical reaction is:
2H₂ + O₂ → 2H₂O
Moles of 250g of H₂ = 250g / 2g/mol = 125mol
From the stoichiometry of the reaction it is clear that,
2 moles of H₂ = produces 2 moles of H₂O
125 moles of H₂ = produces 125 moles of H₂O
Now mass of water will be calculated as:
Mass = (125mol)(18g/mol) = 2,250g
Hence required mass of water is 2,250 grams.
To know more about moles & mass, visit the below link:
brainly.com/question/24631381
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<span>Different elements are composed of different atoms.</span>
