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bearhunter [10]
3 years ago
9

What is the mass, in grams, of 2.50 * 10-3 mol of aluminum sulfate?

Chemistry
1 answer:
Nonamiya [84]3 years ago
5 0

Answer:

The mass is 0.855 grams (option A)

Explanation:

Step 1: Data given

aluminium sulfate = Al2(SO4)3

Numer of moles Al2(SO4)3 = 2.50 * 10^-3 moles

atomic mass Al = 26.99 g/mol

atomic mass S = 32.065 g/mol

Atomic mass O = 16 g/mol

Step 2: Calculate molar mass Al2(SO4)3

Molar mass = 2* 26.99 + 3*32.065 + 12*16

Molar mas = 342.175 g/mol

Step 3: Calculate mass Al2(SO4)3

Mass Al2(SO4)3 = moles Al2(SO4)3 * molar mass Al2(SO4)3

Mass Al2(SO4)3 = 2.5 *10^-3 moles * 342.175 g/mol

Mass Al2(SO4)3 = 0.855 grams

The mass is 0.855 grams (option A)

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<h3><u>Answer;</u></h3>

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<h3><u>Explanation;</u></h3>
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Explanation:

Stereoisomers are two or more atoms that  have the same bonding order of atoms but there is a difference  spatial arrangement of  the  atoms in space.

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From the given question;

Fischer projection for an enantiomer of 2-bromo-2,3-dihydroxypropanal with the bromine oriented horizontally to the left and the hydroxide group oriented horizontally to the right.

we can sketch the way the enantiomer of 2-bromo-2,3-dihydroxypropanal can  be seen like the one shown below:

              CH₂OH

                   |

                   |

                   |

Br -------------|----------------OH

                   |

                   |

                   |

                 CHO

The objective of this question is to drawn the perspective formula of the molecule.

So , from the attached file below; we can see the perspective formula of the molecule in a well structured 3-D format.

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