Answer:
About 1-3 km
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Divide the flow rate (0.750 m³/s) by the cross-sectional area of each pipe:
diameter = 40 mm ==> area = <em>π</em> (0.04 m)² ≈ 0.00503 m²
diameter = 120 mm ==> area = <em>π</em> (0.12 m)² ≈ 0.0452 m²
Then the speed at the end of the 40 mm pipe is
(0.750 m³/s) / (0.00503 m²) ≈ 149.208 m/s ≈ 149 m/s
(0.750 m³/s) / (0.0452 m²) ≈ 16.579 m/s ≈ 16.6 m/s
Answer:
i would say it decreases
Explanation:
bc as distance grows the fields decrease
IM NOT SURE tho
Using the division operation, the <em>number of tubes gotten by each patient </em>can be obtained by <em>dividing 20 by 5</em>. Hence, each patient will get 4 tubes of solution.
<u>Tubes of solution received</u> :
- 10 a.m = 2 tubes
- 12 p.m = 4 tubes
- 3 p.m = 8 tubes
- 6 p.m = 6 tubes
<u>Total tubes received</u> :
- (2 tubes + 4 tubes + 8 tubes + 6 tubes) = 20 tubes
- Number of patients = 5 patients
<u>Number of tubes of solution gotten by each patient</u> :
- (Total tubes of solution ÷ number of patients)
Tubes of solution per patient = (20 ÷ 5) = 4 tubes
Therefore, each patient will get 4 tubes of solution.
Learn more : brainly.com/question/25339242
Answer:
Horizontal component, 
Explanation:
It is given that,
Displacement of the submarine, d = 185 m
It is at an angle of 15 degrees below the horizontal. We need to find the horizontal component of the submarine's displacement. It is given by :
Substituting the values in above equation as :
So, the horizontal component of the submarine’s displacement is 178.69 meters. Hence, this is the required solution.
