The answer is C. You divide 4000 kg/s by 115 kg.
Answer:
0.41s
8.01m/s
Explanation:
Using the formula; v = u + at
Where;
u = initial velocity (m/s)
v = final velocity (m/s)
t = time (s)
a = acceleration (m/s²)
According to the provided information, u = 4m/s, s = 8m,
V = u + at
4 = 0 + 9.8t
4 = 9.8t
t = 0.41s
b) v = u + at
v = 4 + 9.8(0.41)
v = 4 + 4.018
v = 8.018m/s
I):final velocity=initial velocity+acceleration due to gravity*time of travel
Therefore,
v=0+9.8*3.1
=30.38 m/s
If by floor you meant water bed then i think there isn't enough info in the question.
Answer:

Explanation:
Let m is the mass of both cars. The first car is moving with speed v and the other car is moving with speed 2v. The only force acting on both cars is the centripetal force.
For faster car on the road,

v = 2v

..........(1)
For the slower car on the road,
............(2)
Equation (1) becomes,


So, the frictional force required to keep the slower car on the road without skidding is one fourth of the faster car.
Answer:
The approximate change in entropy is -14.72 J/K.
Explanation:
Given that,
Temperature = 22°C
Internal energy 
Final temperature = 16°C
We need to calculate the approximate change in entropy
Using formula of the entropy

Where,
= internal energy
T = average temperature
Put the value in to the formula


Hence, The approximate change in entropy is -14.72 J/K.