g A simple pendulum (consisting of a point mass suspended by a massless string) on the surface of the earth has a period of 1.00

Question

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g A simple pendulum (consisting of a point mass suspended by a massless string) on the surface of the earth has a period of 1.00

s. On a distant planet, a pendulum of identical length but twice the mass is found to have the same period. What is true about the acceleration due to gravity on the distant planet? [Assume both pendulums operate free of any friction or air resistance force]

Physics

1 answer:

leonid [27] · Answer 1 · 2022-08-01T01:53:59+03:00

Answer:

Explanation:

The formula for time period of a pendulum is given as follows :

T = 2π $\sqrt{\frac{l}{g} }$

l is length of pendulum and g is acceleration due to gravity .

So time period of pendulum is not dependent on the mass of the pendulum . If time period is same and length is also the same then acceleration due to gravity will also be the same . Hence the acceleration due to gravity at distant planet will be same as that on the earth.