The movement of electric charge
Answer:
4.022 seconds and 4.99 seconds
Explanation:
Hello!
The free fall of the stone corresponds to a uniformly varied rectilinear movement
d=V_0*t+1/2*g*t^2
Being a free fall the initial speed is zero.
The distance is positive when considered in the same direction and direction as acceleration and speed.
256 feet stone
79.25 m=0 m⁄s*t+1/2*9,8 m⁄s^2 *t^2
t = 4.022 seconds
400 feet stone
121.92m=0 m⁄s*t+1/2*9,8 m⁄s^2 *t^2
t= 4,99 seconds
success with your homework!
Answer:
the ratio of distance travelled by effort to the distance travelled by load in the machine is called velocity ratio (VR)
Answer:
the velocity of the bullet-wood system after the collision is 2.48 m/s
Explanation:
Given;
mass of the bullet, m₀ = 20 g = 0.02 kg
velocity of the bullet, v₀ = 250 m/s
mass of the wood, m₁ = 2 kg
velocity of the wood, v₁ = 0
Let the velocity of the bullet-wood system after collision = v
Apply the principle of conservation of linear momentum to calculate the final velocity of the system;
Initial momentum = final momentum
m₀v₀ + m₁v₁ = v(m₀ + m₁)
0.02 x 250 + 2 x 0 = v(2 + 0.02)
5 + 0 = v(2.02)
5 = 2.02v
v = 5/2.02
v = 2.48 m/s
Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s
