A.) x + 8 < 14
-8 -8
x < 6
b.) x - 12 >/= 5.7
+12 +12
x >/= 17.7
To solve for the A or the principal amount plus interest you can use two formulas:
A = P + I
Where: P = Principal
I = Interest
or you can use
A = P (1+ rt)
Where: P = principal
r = rate in decimal
t = time in years
With your given you can use the second one, without having to use the first.
Given that the Principal amount is $222 and the rate is 12% and time is 10 years, we first need to convert your rate into decimal by dividing the value in percent by 100 which will yield 0.12.
Then now we can just input the data that you know into the formula:
A = P(1+ rt)
= $222(1 + (0.12)(10))
= $222(2.2)
= $488.40
Your A is then equal to $488.40
If you need to get the simple interest all you need to use is the first formula given:
A = P + I
for the interest you transpose the P to the side of the A and you will get:
I = A - P
= $488.40 - $222
= $266.40
$266.40 is the added interest to the principal amount.
Answer:
cosjk = √55 i/3
tanjk = 8/√55 i
Step-by-step explanation:
Given
sin jk = 8/3
According to SOH CAH TOA
Sin theta = opposite/hypotenuse = 8/3
Opposite = 8
hypotenuse = 3
Get the adjacent using the pythagoras theorem
hyp² = opp²+adj²
adj² = hyp² - opp²
adj² = 3² - 8²
adj² = 9-64
adj² = -55
adj = √-55
adj = √55 i (i = √-1)
Get cosjk
cosjk = adj/hyp
cosjk = √55 i/3
Get tanjk
tanjk = opp/adj
tanjk = 8/√55 i
Answer:
Step-by-step explanation:
If you look at the objects thrown as garbage, it's a two- or three-dimensional item that takes up space and also has mass and this is a solid waste.
And the landfill that dumps such garbage is also three-dimensional.
Hence, the volume module, if the object inside is a solid, either would be
As household numbers rise, landfill space increases.
So,
If H represents the number of household keeps, then it will be a sufficient unit for the purpose of Sophia that is
