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Q18
360 = 0.2 a
a = 360 / .2 = 5(360)= 1800 audience members
Q19
Assuming the information is consistent we ignore the trapezoid; we have two triangles base 1.1 height 3.8 so the area for the pair is 2 (1/2) (1.1) (3.8) = 4.18 sq inches.
Q20
6(5)^2 - 5(4) + 8 = 6(25) -20 + 8 = 150 - 20 + 8 = 138
Q21
This is an LCM or least common multiple problem
LCM(12,8) = LCM(3(4),2(4))=3(2)(4)=24 weeks
Answer:
The answer is no, it cannot be 11 inches
Step-by-step explanation:
If the width is 5 inches and the area must be less than 55 square inches,
5 x 11 = 55
55 = 55
It is asking if
55 < 55
Answer:
9.2
Step-by-step explanation:
Use law of sines
a/sinA = b/sinB
5/sin 31 = b/sin 108
b=9.2
Answer:
3p³ + 2p² – 3p – 11
Step-by-step explanation:
From the question given above, the following data were obtained:
Side 1 (S₁) = –1(p + 5)
Side 2 (S₂) = 2(p² – 3)
Side 3 (S₃) = 3p³ – 2p
Perimeter (P) =?
The perimeter of the triangle can be obtained as follow
P = S₁ + S₂ + S₃
P = –1(p + 5) + 2(p² – 3) + 3p³ – 2p
Clear bracket
P = –p – 5 + 2p² – 6 + 3p³ – 2p
Rearrange
P = 3p³ + 2p² – 2p – p – 6 – 5
P = 3p³ + 2p² – 3p – 11
Therefore, the perimeter of the triangle is 3p³ + 2p² – 3p – 11
