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Lemur [1.5K]
3 years ago
12

Find the rate of change for the situation. You run 3 miles in one hour and 6 miles in two hours

Mathematics
1 answer:
Harman [31]3 years ago
8 0
3x1=3
6x2=12
12+3=15
the anser is 15
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Which expression shows the result of applying the distributive property to 3 (1/5x - 1/7)
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Hi,

3(1/5x - 1/7)

= 3/5x - 3/7

B

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3 0
2 years ago
5s + 2z = 1.32 <br> 3s + 1z = 0.75 <br> what would the answer be?
Sphinxa [80]

Answer:                                                                    

Step-by-step explanation:

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A) x • 3 + 4 = 22
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7 0
3 years ago
The mean high temperature on a particular day in January is 31 degrees F and the standard deviation is 8.7 degrees. One year, th
Basile [38]

Answer:

The Z-score for that day's temperature is 2.41, and since Z > 2, this temperature is significantly high.

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

If |Z| > 2, the measure X is significantly high(Z > 2) or significantly low(Z < -2).

The mean high temperature on a particular day in January is 31 degrees F and the standard deviation is 8.7 degrees.

This means that \mu = 31, \sigma = 8.7

One year, the temperature was 52 degrees F on that day.

This means that X = 52.

What is the Z-score for that day's temperature?

Z = \frac{X - \mu}{\sigma}

Z = \frac{52 - 31}{8.7}

Z = 2.41

The Z-score for that day's temperature is 2.41, and since Z > 2, this temperature is significantly high.

8 0
2 years ago
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