Given A = {(1, 3)(-1, 5)(6, 4)}, B = {(2, 0)(4, 6)(-4, 5)(0, 0)} and C = {(1, 1)(0, 2)(0, 3)(0, 4)(-3, 5)}, answer the following
Nuetrik [128]
Answer:
Domain of set B: {2, 4, -4, 0}
Step-by-step explanation:
The domain of the function whose ordered pairs are listed in set B is the set of first numbers of those pairs: {2, 4, -4, 0}.
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<em>Comment on the question</em>
A "set" does not have a domain. A "function" has a domain. To make any sense of this question, we have to interpret the question to mean the function described by the ordered pairs in the set.
Answer:-14, -26
Step-by-step explanation:
13-4=9
4-9=-5
From here you can see that the pattern is -9
-5-9=-14
23. is -14
16-2=14
2-14=-12
From here you can see that the pattern is -14
-12-14=-26
24. is -14
Answer:
Step-by-step explanation:
Firstly, note that -2i really is just z = 0 + (-2)i, so we see that Re(z) = 0 and Im(z) = -2.
When we're going from Cartesian to polar coordinates, we need to be aware of a few things! With Cartesian coordinates, we are dealing explicitly with x = blah and y = blah. With polar coordinates, we are looking at the same plane but with angle and magnitude in consideration.
Graphing z = -2i on the Argand diagram will look like a segment of the y axis. So we ask ourselves "What angle does this make with the positive x axis? One answer you could ask yourself is -90°! But at the same time, it's 270°! Why do you think this is the case?
What about the magnitude? How far is "-2i" stretched from the typical "i". And the answer is -2! Well... really it gets stretched by a factor of 2 but in the negative direction!
Putting all of this together gives us:
z = |mag|*(cos(angle) + isin(angle))
= 2*cos(270°) + isin(270°)).
To verify, let's consider what cos(270°) and sin(270°) are.
If you graph cos(x) and look at 270°, you get 0.
If you graph sin(x) and look at 270°, you get -1.
So 2*(cos(270°) + isin(270°)) = 2(0 + -1*i) = -2i as expected.
Answer:
45
Step-by-step explanation:
Since this is only three terms
Find the three terms and add
j=1 3(1)^2+1 = 3+1 =4
j=2 3(2)^2+1 = 3(4)+1 =13
j=3 3(9)^2+1 = 27+1 =28
The sum is 4+13+28 =45
Answer:
a . domain 5,0,7,9,0
range -2,-2,-4,8,2
b. domain 2,4,8,9
range 1,2,4,11
Step-by-step explanation:
<h3>a is not a function</h3>
because function is a relationship in which each domain element occurs only once.
<h3>b is a function</h3>
