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Dennis_Churaev [7]
3 years ago
6

Given the sequence:1,-1/3,1/9,-1/27,... Find

Mathematics
1 answer:
CaHeK987 [17]3 years ago
6 0

We can find the following pattern:

a_1 = 1 = (-1)^0\cdot\dfrac{1}{3^0}

a_2 = -\dfrac{1}{3} = (-1)^1\cdot\dfrac{1}{3^1}

a_3 = \dfrac{1}{9} = (-1)^2\cdot\dfrac{1}{3^2}

a_4 = \dfrac{1}{27} = (-1)^3\cdot\dfrac{1}{3^3}

We can deduce the generic rule

a_n = (-1)^{n-1}\cdot\dfrac{1}{3^{n-1}}

And thus

a_{15} = (-1)^{14}\cdot\dfrac{1}{3^{14}}

With this rule, you can compute the 5th, 6th, 7th, 8th, 9th and 10th element and sum them.

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