Answer:
The correct option is C. either a t test or an analysis of variance can be performed.
Step-by-step explanation:
Consider the provided information.
- The t-test, is used for whether the means of two groups are equal or not. The assumption for the test is that both groups are sampled from normal distributions with equal variances.
- Analysis of Variance (ANOVA) is a statistical method evaluating variations between two or more methods. ANOVA is used in a study to analyze the gaps between group methods.
- ANOVA is used not for specific differences between means, but for general testing.
- The chi-squared test is often used to evaluate whether there was a significant difference in one or more groups between the predicted frequencies and the observed frequencies.
Hence, Either a t test or an analysis of variance can be performed to determine whether the means of two population are equal.
Therefore, the correct option is C. either a t test or an analysis of variance can be performed.
Answer:
see explanation
Step-by-step explanation:
6 × 24 ← replace 24 by 4 + 20
= 6(4 + 20) ← multiply each term in the parenthesis by 6
= 24 + 120
= 124
Answer: −3a(−2b−4y).−5x(−2b−4y). to this
6ab+12ay+10bx+20xy
Step-by-step explanation: hope this helps :)
Answer:
Am am not that big brain
Step-by-step explanation:
The correct answer is false the order should be
Step 1
Step 3
Step 5
Step 2
Step 6
Step 4
Step 7
