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2 years ago

Usually, when the temperature is increased, what will happen to the rate of dissolving?

Physics

1 answer:

ArbitrLikvidat [17]2 years ago

5 0

It will decrease

When the temperature increased, the rate will decrease

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Vinvika [58]

Answer:

Road A = 8 meters Wet

Road B = 2 meters Muddy

Road C = 12 meters Dry

Explanation:

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2 years ago

How are size and mass of the moon different from that of the earth?

Elodia [21]

<span>The diameter of the Moon is 3,474 km. Now, let's compare this to the Earth. The diameter of the Earth is 12,742 km. This means that the Moon is approximately 27% the size of the Earth.</span>

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2 years ago

The format specifier ________ is a placeholder for an int value. %d %n %int %s

Grace [21]

%d is a format specifier that is a placeholder for an int value. It tells the compiler that we want to print an integer value that is present in variable a. In this way there are several format specifiers in c.

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3 years ago

The brakes on your automobile are capable of creating a deceleration of 4.6 m/s^2. If you are going 114 km/h and suddenly see a

drek231 [11]

Answer:

The minimum time to get the car under max. speed limit of 79 km/h is 2.11 seconds.

Explanation:

$a=\frac{V_f-V_0}{t}$

isolating "t" from this equation:

$t=\frac{V_f-V_0}{a}$

Where:

a= $-4.6m/s^2$ (negative because is decelerating)

$V_f= 79 km/h$

$V_0= 114 km/h$

First we must convert velocity from km/h to m/s to be consistent with units.

$79\frac{km}{h}*\frac{1000m}{1 km}*\frac{1h}{3600s}=\frac{79*1000}{3600}=21.94 m/s$

$114\frac{km}{h}*\frac{1000m}{1 km}*\frac{1h}{3600s}=\frac{114*1000}{3600}=31.67 m/s$

So;

$t=\frac{V_f-V_0}{a}=\frac{21.94 m/s-31.66m/s}{-4.6 m/s^2}=2.11 s$

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3 years ago

A car travels from point A to Be in 3 hours and returns back to point A in 5 hours .Points A and B are 150 miles apart along str

Rainbow [258]

Explanation:

Given that,

The time taken from A to B is 3 hours

The time from B to A = 5 hours

The total distance between A and B is 150 miles

The average velocity from A to B,

$v=\dfrac{150}{3}=50\ mph$

The average velocity from B to A,

$v=\dfrac{150}{5}=30\ mph$

As the velocity of an object is a vector quantity. It means when the car reaches the initial point, the displacement is 0. So, the average velocity is equal to 0.

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2 years ago