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il63 [147K]
3 years ago
15

In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, th

e note at 110 Hz has two strings at this frequency. If one string slips from its normal tension of 596 N to 538.00 N, what beat frequency is heard when the hammer strikes the two strings simultaneously
Physics
1 answer:
pav-90 [236]3 years ago
3 0

Answer:

5.4893 beats/sec

Explanation:

We have f_1 and f_2 as frequency of two waves

also we know that according to question

f_2=f_1\sqrt{\frac{F'}{F} }

F and F' are forces on the two frequencies.

therefore, beat frequency is

f=f_1-f_2=f_1-f_1\sqrt{\frac{F'}{F} }\\=110(1-\sqrt{\frac{538}{596} })\\=5.4893 \text{ beats/sec}

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