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3 years ago

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In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, th

e note at 110 Hz has two strings at this frequency. If one string slips from its normal tension of 596 N to 538.00 N, what beat frequency is heard when the hammer strikes the two strings simultaneously

1 answer:

pav-90 [236]3 years ago

3 0

Answer:

5.4893 beats/sec

Explanation:

We have f_1 and f_2 as frequency of two waves

also we know that according to question

$f_2=f_1\sqrt{\frac{F'}{F} }$

F and F' are forces on the two frequencies.

therefore, beat frequency is

$f=f_1-f_2=f_1-f_1\sqrt{\frac{F'}{F} }\\=110(1-\sqrt{\frac{538}{596} })\\=5.4893 \text{ beats/sec}$

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Answer:

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