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olasank [31]
3 years ago
14

A 10 N force and an 18 N force act in the same direction on an object. What is the net force on the object?

Physics
1 answer:
Annette [7]3 years ago
6 0

Answer:

28 N

Explanation:

From the question given above, we were told that 10 N force and 18 N force act in the same direction on the object.

The net force acting on the object can be obtained by simply adding both forces together since they both act on the object in the same direction. This is illustrated below:

Force 1 (F₁) = 10 N

Force 2 (F₂) = 18 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂ (since they both act in the same direction)

Fₙ = 10 + 18

Fₙ = 28 N

Therefore, the net force acting on the object is 28 N.

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A ball is thrown vertically upward from the edge of a bridge 22.0 m high with an initial speed of 16.0 m/s. The ball falls all t
KonstantinChe [14]

To solve this problem we will apply the concepts related to the kinematic equations of motion. We will start calculating the maximum height with the given speed, and once the total height of fall is obtained, we will proceed to calculate with the same formula and the new height, the speed of fall.

The expression to find the change in velocity and the height is,

v_f^2-v_0^2 = -2gh

Replacing,

0^2-16^2 = -2(9.8)h

h = 13.0612m

Thus the total height reached by the ball is

H = 22m+13.0612m

H = 35.0612m

Now calculate the velocity while dropping down from the maximum height as follows

v_f^2-v_0^2 = 2gh

Substituting the new height,

v_f^2 - 0^2 = 2(9.8)(35.0612)

v = \sqrt{687.2}

v = 26.2145m/s

3 0
3 years ago
Cousin Throckmorton is playing with the clothesline. One end of the clothesline is attached to a vertical post. Throcky holds th
Oksi-84 [34.3K]

Answer:

The  frequencies are  f_n  =  n (0.875 )

Explanation:

From the question we are told that

   The speed of the wave is  v  =  0.700 \  m/s

   The  length of vibrating  clothesline is  L  =  40.0 \  cm = 0.4 \ m

Generally the fundamental frequency is  mathematically represented as

        f =  \frac{v}{2 L  }

=>     f =  \frac{ 0.700 }{2 *  0.4   }

=>     f =  0.875 \  Hz

Now  this other frequencies of vibration experience by the clotheslines are know as harmonics and they are obtained by integer multiple of  the fundamental frequency

So  

   The  frequencies are mathematically represented as

       f_n  =  n  * f

=>     f_n  =  n (0.875 )

Where  n  =  1, 2, 3 ....

       

3 0
3 years ago
When a man travel from hilly to terai what will happen to weight and why?
juin [17]

Answer:

When a man travels from Hilly region to Terai region, his weight gradually increases because the value of g is more at the Terai region than that in hilly region. 3. An object weights 20 N in air and 16 N in liquid, then answer the following questions.

Explanation:

because the value of g is more at the Terai region than that in hilly region. 3. An object weights 20 N in air and 16 N in liquid, then answer the following questions.

6 0
3 years ago
During anomalous expansion of water ,heat transfer is limited to conduction and radiation only ,explain.​
aalyn [17]

Heat transfer is limited to conduction and radiation only in anomalous expansion of water simply because of the temperature at which the expansion occurs and density

<h3>What is anomalous expansion of water?</h3>

Anomalous expansion of water is a property of water in which water expands instead of contracting.

  • Anomalous expansion of water makes water less dense.
  • The major effect of this anomalous expansion it will still remain less dense and at the surface of water.
  • Interestingly, this expansion occurs when it is cooled from 4°C to 0°C.

Learn more about properties of water:

brainly.com/question/18681949

4 0
2 years ago
A projectile is launched from the ground at an angle of 60o above the horizontal. At what point in its trajectory does it have t
Elodia [21]

Answer:

It's constant everywhere in its trajectory.

Explanation:

the projectile was launched with an initial velocity, the only acceleration that is affecting the projectile's velocity is gravity.

The acceleration of gravity is practically equal everywhere on earth, so during its trajectory, we have to take into consideration only the acceleration because of gravity.

This is only correct because the projectile was launched with an initial velocity and it's not accelerating from rest and then falls.

5 0
3 years ago
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