The greatest number can be as large as 81.
<u>Step-by-step explanation:</u>
Given that,
- A set of five different positive integers has a mean of 33 and a median of 40.
- We need to find the set of five different positive integers.
We already know that,
- The term "median" is the middle term which is 40.
- Therefore, if you do not include 0 in positive integers, then the first two positive integers below the median value of 40 to be as low as possible are 1 and 2.
- The median 40 will be the third positive integer of the set.
- Therefore, the fourth positive integer should be the next lowest possible value of 40 which is 41.
With simple algebra you can figure out the last greater number.
-
The set of five different positive integers is given as {1,2,40,41,x}.
- Let, x be the last greater number in the set.
The term "mean" is defined as the sum of all the integers in the set divided by the number of integers in the set.
⇒ Mean = (1+2+40+41+x) / 5
⇒ 33 = (84+x) / 5
⇒ 33×5 = 84 + x
⇒ 165 - 84 = x
⇒ 81 = x
∴ The greatest number can be as large as 81.
Answer is a because -1 just means the opposite
Answer:
-24
Step-by-step explanation:
The integer in "elevation of -24 meters" is -24.
The linear form of the vector u = (47, -29) is given by:
D. u = 47i − 29j
<h3>What is the linear form of a vector (a,b)?</h3>
The linear form of a vector u = (a,b) is given by:
u = ai + bj.
In this problem, the vector is u = (47, -29), hence the linear form is given by:
D. u = 47i − 29j
More can be learned about vectors at brainly.com/question/24606590
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