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Brrunno [24]
3 years ago
15

What is this question, 27.

Mathematics
1 answer:
Sidana [21]3 years ago
8 0
There are 12 months so find the month that the 2 payments will be the same. Dose not matter the date just the month.
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Patty’s gymnastics class is 5
Ann [662]

Answer:

possibly 11 hours on each which is embarrassing

8 0
3 years ago
HELP <br> H E L P !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Anastasy [175]

Answer:

subject?

Step-by-step explanation:

5 0
3 years ago
Line p goes through points (-2,6) and (4,-3) what is the equation of line p ​
marin [14]

Answer:

hello : y =(-3/2)x+3

Step-by-step explanation:

Hello : let  A(-2,6)    B(4,-3)

the slope is :   (YB - YA)/(XB -XA)

(-3-6)/(4+2)  = -3/2

an equation is : y=ax+b     a is a slope

y = (-3/2)x +b

 

the line through point  (-2,6) :  6 = (-3/2)(-2)+b

b =3  

the equation is : y =(-3/2)x+3

5 0
3 years ago
What is the equation of the line that is perpendicular to -2/5x-7 and passes through (4,-1)?
alukav5142 [94]

Step-by-step explanation:

maybe this is not the full expression, as you wrote the line equation in a funny way.

I understand the following :

the line is

y = (-2/5)×x - 7

perpendicular means crossing at a right angle (90 degrees).

the slope of the original line is -2/5.

as in every line equation, the slope is the factor of x. and it expresses the ratio y/x indicating the amount of units y is changing, when x changes a certain amount of units (e.g. when going from one point on the line to another).

the perpendicular slope turns the original y/x ratio upside-down, and also flips the sign.

so, it is 5/2.

the equation for the perpendicular line looks like

y = (5/2)×x + b

now what is b ?

for this we use the specified point on the line : (4, -1)

and we put these values as x and y into the equation :

-1 = (5/2)×4 + b = 5×2 + b = 10 + b

b = -11

and so, the full equation of the perpendicular line is

y = (5/2)×x - 11

3 0
2 years ago
Please help!! With step by step
Sever21 [200]

Answer:

R=\$145.12

Step-by-step explanation:

<u>Compound Interest</u>

This is a well-know problem were we want to calculate the regular payment R needed to pay a principal P in n periods with a known rate of interest i.

The present value PV or the principal can be calculated with

P=F_a\cdot R

Solving for R

\displaystyle R=\frac{P}{F_a}

Where Fa is computed by

\displaystyle F_a=\frac{1-(1+i)^{-n}}{i}

We'll use the provided values but we need to convert them first to monthly payments

i=7\%=7/(12\cdot 100)=0.00583

n=3*12=36

\displaystyle F_a=\frac{1-(1+0.00583)^{-36}}{0.00583}

F_a=32.386

Thus, each payment is

\displaystyle R=\frac{4,700}{32.386}=145.12

\boxed{R=\$145.12}

4 0
3 years ago
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