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maksim [4K]
3 years ago
5

How can I get straight A's

Mathematics
2 answers:
svetlana [45]3 years ago
8 0
You should take notes during class and do revisions when you get home always write down your home work study stuff like that
Aloiza [94]3 years ago
7 0
By being smart...
Or studying and listening and taking notes in class
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What is the simplest form of the ratio 18b^2 to 45b
Svetradugi [14.3K]
Treat it like a fraction
18b^2/45b
divide top and bottom by b
18b/45
divide top and bottom by 3
6b/15
divide top and bottom by 3 again
2b/5
2b:5 is the simpliest form of the ratio
7 0
4 years ago
Write the first ten terms of a sequence whose first term is -10 and whose common difference is -2.
Nesterboy [21]
Add the common difference to a term to get the next term.
-10
-10 + (-2) = -12
-12 + (-2) = -14
etc.

The sequence is
-10, -12, -14, -16, -18, -20, -22, -24, -26, -28
3 0
3 years ago
When constructing the centroid of a triangle, the intersection of all three of which type of line is needed?
8090 [49]
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4 0
3 years ago
Evaluate the series
dalvyx [7]

Answer:

the value of the series;

\sum_{k=1}^{6}(25-k^2) = 59

C) 59

Step-by-step explanation:

Recall that;

\sum_{1}^{n}a_n = a_1+a_2+...+a_n\\

Therefore, we can evaluate the series;

\sum_{k=1}^{6}(25-k^2)

by summing the values of the series within that interval.

the values of the series are evaluated by substituting the corresponding values of k into the equation.

\sum_{k=1}^{6}(25-k^2) =(25-1^2)+(25-2^2)+(25-3^2)+(25-4^2)+(25-5^2)+(25-6^2)\\\sum_{k=1}^{6}(25-k^2) =(25-1)+(25-4)+(25-9)+(25-16)+(25-25)+(25-36)\\\sum_{k=1}^{6}(25-k^2) =24+21+16+9+0+(-11)\\\sum_{k=1}^{6}(25-k^2) = 59\\

So, the value of the series;

\sum_{k=1}^{6}(25-k^2) = 59

6 0
4 years ago
Find the area of the figure above.
madam [21]

Step-by-step explanation:

1/2·3.14·(12/2)^2 + 12·40 + 1/2·12·5 = 566.52 square feet

4 0
3 years ago
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