The graphed polynomial seems to have a degree of 2, so the degree can be 4 and not 5.
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Could the graphed function have a degree 4?</h3>
For a polynomial of degree N, we have (N - 1) changes of curvature.
This means that a quadratic function (degree 2) has only one change (like in the graph).
Then for a cubic function (degree 3) there are two, and so on.
So. a polynomial of degree 4 should have 3 changes. Naturally, if the coefficients of the powers 4 and 3 are really small, the function will behave like a quadratic for smaller values of x, but for larger values of x the terms of higher power will affect more, while here we only see that as x grows, the arms of the graph only go upwards (we don't know what happens after).
Then we can write:
y = a*x^4 + c*x^2 + d
That is a polynomial of degree 4, but if we choose x^2 = u
y = a*u^2 + c*u + d
So it is equivalent to a quadratic polynomial.
Then the graph can represent a function of degree 4 (but not 5, as we can't perform the same trick with an odd power).
If you want to learn more about polynomials:
brainly.com/question/4142886
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Answer:
f=-9
Step-by-step explanation:
peremeter =l.muttiply by b,so 5.multiply by 3=15
Given points are (6,7) and (2,-1). Now we have to find the equation of line that doesn't passes through these two points.
Since choices are missing to I will find equation of line passing through those points first then any choice which is not equivalent or same as the obtained equation will be the answer.
Slope is given by formula :
Now plug m=2 and any point say (2,-1) into y=mx+b
-1=2*2+b
-1=4+b
-5=b
plug m=2 and y=-5 into y=mx+b
So the line passing through given points is y=2x-5
Hence any choice which is not equivalent or same as the obtained equation y=2x-5 will be the answer.
