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8090 [49]
4 years ago
10

The mapping diagram shows a functional relationship.

Mathematics
1 answer:
irga5000 [103]4 years ago
5 0

Answer:

its -1

Step-by-step explanation:

cuz

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Use the box method to distribute and simplify (3x – 1)(-5x + 1)
Softa [21]

Answer:

-15x^2 +8x -1

Step-by-step explanation:

(3x – 1)(-5x + 1)=

3x(-5x) + 3x(1) - 1(-5x) -1 =

-15x^2 +3x +5x -1 =

-15x^2 +8x -1

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4 0
3 years ago
Question 1
arlik [135]

Answer:

30

Step-by-step explanation:

This problem can be done without the Distance Formula (which is a way to find the distance between any two points in the plane).

The attached image shows the points and segments joining them.

PQ = 5 because the points are on the same horizontal line, and you can count spaces between them (or subtract x-coordinates: 4 - (-1) = 5).

PR = 12 because the points are on the same vertical line; count spaces or subtract y-coordinates, 7 - (-5) = 12.

The triangle is a right triangle, so the Pythagorean Theorem can be used to find the length of the hypotenuse.

(\text{leg})^2+(\text{leg})^2=(\text{hypotenuse})^2

(QR)^2=5^2+12^2=25+144=169\\QR=\sqrt{169}=13

The perimeter of the triangle is 5 + 12 + 13 = 30

6 0
3 years ago
Identify the like terms in the expression. -3x^2+3x-x^2-2+6x
ololo11 [35]

like terms: -3x^2, -x^2

and 3x, 6x

6 0
3 years ago
In the game of blackjack played with one​ deck, a player is initially dealt 2 different cards from the 52 different cards in the
Volgvan

Answer:

P =4.83\%

Step-by-step explanation:

First we calculate the number of possible ways to select 2 cards an ace and a card of 10 points.

There are 4 ace in the deck

There are 16 cards of 10 points in the deck

To make this calculation we use the formula of combinations

nCr=\frac{n!}{r!(n-r)!}

Where n is the total number of letters and r are chosen from them

The number of ways to choose 1 As is:

4C1 = 4

The number of ways to choose a 10-point letter is:

16C1 = 16

Therefore, the number of ways to choose an Ace and a 10-point card is:

4C1 * 16C1 = 4 * 16 = 64

Now the number of ways to choose any 2 cards from a deck of 52 cards is:

52C2 =\frac{52!}{2!(52-2)!}

52C2 = 1326

Therefore, the probability of obtaining an "blackjack" is:

P = \frac{4C1 * 16C1}{52C2}

P = \frac{64}{1326}

P = \frac{32}{663}

P =0.0483

P =4.83\%

4 0
3 years ago
Read 2 more answers
3x^2 - 12x ÷ x-4 what is this simplified
Andreyy89
<span>3<span>x^2</span></span>−<span>16 I think that's the answer. Hope that helps!</span>
8 0
3 years ago
Read 2 more answers
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