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shepuryov [24]
3 years ago
13

Two car-rental agencies are competing for business. Mertz charges $35 a day and $0.15 per mile, and Mavis charges $20 a day and

$0.45 per mile. a. Write an equation that represents the charges to rent a car at each agency.
Mathematics
1 answer:
Nata [24]3 years ago
6 0
Well we overall have two different equations we can make here with two different variables. If 35 & 20 were to be our daily charge, and y is our per mile charge, we can infer that x times y is equal to our overall car-rental price, so if we set it out correctly, our equations should be
35 x (y).15 =
20 x (y).45 = 
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Answer:

6.75 pounds

Step-by-step explanation:

This question is of direct variation. We will use x as our answer. 8 is 2/3 of 12, so 4.5 should be 2/3 of x. We can now make an equation.

4.5=\frac{2}{3} x\\4.5*\frac{3}{2} =\frac{2}{3} x*\frac{3}{2} \\6.75=x

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Please!!! Help!!! Brainliest of Right! it goes as 50 point in the end but i used 100 point if you help me i will help you!!
vekshin1

Answer:

2.  3.913 kg (3 dp)

3.  light cream

4.  240 CoffeeStops

5.  7 CoffeeStops per square mile

6.  2,861 cups of coffee each day

Step-by-step explanation:

Given:

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  • Light cream density at 20 °C = 1.012 kg/l
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<u>Question 2</u>

\begin{aligned}\textsf{1 gallon} & = \sf \dfrac{1}{0.264}\:liters\\\\\implies \textsf{Mass (1 gallon of skim milk)} & = \sf Density \times Volume\\& = \sf 1.033\:kg/l \times \dfrac{1}{0.264}\:l\\& = \sf 3.913\:kg\:(3\:dp)\end{aligned}

Therefore, the mass of 1 gallon of skim milk is 3.913 kg (3 dp)

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<u>Question 3</u>

Given:

  • Volume of liquid = 9 liters
  • Mass of liquid = 9.108 kg

\begin{aligned}\implies \sf Density & = \sf \dfrac{Mass}{Volume}\\\\& = \sf \dfrac{9.108\:kg}{9\:l}\\\\& = \sf 1.012\:kg/l \end{alilgned}

Therefore, the container holds light cream.

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<u>Question 4</u>

Given:

  • 15 CoffeeStops per 100,000 people
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\begin{aligned}\implies \textsf{Number of Coffeestops} & = \sf \dfrac{population}{density}\\\\& = \sf \dfrac{1,602,000}{100,000/15}\\\\& = \sf \dfrac{1,602,000}{100,000} \times 15\\\\& = \sf 240.3\end{aligned}

Therefore, there are 240 CoffeeStops.

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<u>Question 5</u>

Given

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\begin{aligned}\implies \textsf{CoffeeStops density} & = \sf \dfrac{number\:of\:stores}{land\:area}\\\\& = \sf \dfrac{240}{34}\\\\& \approx \sf 7 \: \textsf{CoffeeStops per square mile}\end{aligned}

Therefore, the density of CoffeeStops is 7 per square mile.

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Given:

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\begin{aligned}\implies \textsf{Cups served each week} & = \textsf{number of people} \times \textsf{number of cups per week}\\& = \sf 1,602,000 \times 3\\& = \sf 4,806,000\: \textsf{cups per week}\\\\\implies \textsf{Cups per day} & = \sf \dfrac{\textsf{cups per week}}{\textsf{days in a week}}\\\\& = \sf \dfrac{4,806,000}{7}\\\\& = \sf 686,571\:\textsf{(nearest whole number)}\end{aligned}

\begin{aligned}\implies \textsf{Cups served per day per shop} & = \dfrac{\textsf{cups per day}}{\textsf{number of shops}}\\\\& = \sf \dfrac{686,571}{240}\\\\& = \sf 2,861\: \textsf{(nearest whole number)} \end{aligned}

Therefore, each Manhattan CoffeeStop serves approximately 2,861 cups of coffee each day.

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