Answer:
0.05547
Step-by-step explanation:
Given :
_____Peter __ Alan __ Sui__total
Before 1838 __ 418 ___1475 _3731
After _ 1420 __ 329 ___1140_2889
Total _3258 __ 747 __ 2615 _6620
The expected frequency = (Row total * column total) / N
N = grand total = 6620
Using calculator :
Expected values are :
1836.19 __ 421.006 __ 1473.8
1421.81 ___325.994__ 1141.2
χ² = Σ(Observed - Expected)² / Expected
χ² = (0.00177817 + 0.0214571 + 0.000974852 + 0.00229642 + 0.0277108 + 0.00125897)
χ² = 0.05547
A)
SLOPE OF f(x)
To find the slope of f(x) we pick two points on the function and use the slope formula. Each point can be written (x, f(x) ) so we are given three points in the table. These are: (-1, -3) , (0,0) and (1,3). We can also refer to the points as (x,y). We call one of the points

and another

. It doesn't matter which two points we use, we will always get the same slope. I suggest we use (0,0) as one of the points since zeros are easy to work with.
Let's pick as follows:


The slope formula is:
We now substitute the values we got from the points to obtain.

The slope of f(x) = 3
SLOPE OF g(x)
The equation of a line is y=mx+b where m is the slope and b is the y intercept. Since g(x) is given in this form, the number in front of the x is the slope and the number by itself is the y-intercept.
That is, since g(x)=7x+2 the slope is 7 and the y-intercept is 2.
The slope of g(x) = 2
B)
Y-INTERCEPT OF g(x)
From the work in part a we know the y-intercept of g(x) is 2.
Y-INTERCEPT OF f(x)
The y-intercept is the y-coordinate of the point where the line crosses the y-axis. This point will always have an x-coordinate of 0 which is why we need only identify the y-coordinate. Since you are given the point (0,0) which has an x-coordinate of 0 this must be the point where the line crosses the y-axis. Since the point also has a y-coordinate of 0, it's y-intercept is 0
So the function g(x) has the greater y-intercept
What are the answers being provided ?
Answer:
In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -
one side of triangle = 6/2 =3 (half of the diagonal)
other side = 8/2 = 4
a^2 + b^2 = c2
3 ^2 + 4^2 = c^2
9+16 = c^2
c^2=25
c =
= 5
the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !
Its b and a hope this helps