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3 years ago

Determine whether the three points are the vertices of a right triangle.

Mathematics

1 answer:

solniwko [45]3 years ago

7 0

Answer:

Step-by-step explanation:

We plot the points (x,y) in the coordinate system and the points are shown in the diagram attached.

We can draw a line y = -6 connecting the RED and BLUE points. Also, we can draw a line x = 9 connecting the BLUE and GREEN points.

The intersection of these two PERPENDICULAR LINES is at the point (9, -6) (as seen --- The blue point). So, when two perpendicular lines intersect, that point is a right angle.

So, the 3 points given INDEED make a right triangle.

So, correct answer is A

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What part of a<br>a dozen is 8?

Murljashka [212]

Answer:

$\frac{2}{3}$

0.67

Step-by-step explanation:

a dozen is 12

12/4 = 3

8/4 = 2

8 is 2/3 of a dozen(12)

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2 years ago

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Which equals the product of (x-3)(2x + 1)? 222 – 7x - 3 22 – 5x - 3 3x = 2 6,2

Katena32 [7]

Answer:

Step-by-step explanation:

$2 {x}^{2} - 5x - 3$

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2 years ago

If y is inversely proportional to the square root of x and y=−70 when x=49, find y if x=2401.

Dahasolnce [82]

The value of y when x= 2401 is -10

<h3>How to determine the value of x?</h3>

An inverse variation is represented as:

$y = \frac{k}{\sqrt x}$

Where k is the proportionality constant

When y = -70, x = 49

So, we have:

$-70 = \frac{k}{\sqrt {49}}$

Take the square root of 49

$-70 = \frac{k}{7}$

Multiply through by 7

k = -490

Substitute k = -490 in $y = \frac{k}{\sqrt x}$

$y = -\frac{490}{\sqrt x}$

When x =2401, we have

$y = -\frac{490}{\sqrt {2401}}$

Evaluate the square root

$y = -\frac{490}{49}$

Divide

y = -10

Hence, the value of y when x= 2401 is -10