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Artyom0805 [142]
4 years ago
8

Use elimination to solve each system of equations 2x-y=-1 3x-2y=1

Mathematics
2 answers:
mixer [17]4 years ago
8 0
2x-y=-1 \ \ \ |\times (-2) \\
3x-2y=1 \\ \\
-4x+2y=2 \\
\underline{3x-2y=1 \ \ \ \ } \\
-4x+3x=2+1 \\
-x=3 \ \ \ |\times (-1) \\
x=-3 \\ \\
2x-y=-1 \\
2 \times (-3)-y=-1 \\
-6-y=-1 \ \ \ |+6 \\
-y=5 \ \ \ |\times (-1) \\
y=-5 \\ \\
\boxed{(x,y)=(-3,-5)}
TEA [102]4 years ago
4 0
2x - y = -1
<u>3x - 2y = 1</u>
5x - 3y = 0
5x - 5x - 3y = 0 - 5x
3y = 0 - 5x
<u>3y</u> = <u>0 - 5x</u>
 3        3
y = 0 - 5/3x
3x - 2(0 - 5/3x) = 1
3x + 8/3x = 1
5 1/4x = 1
<u>5 1/4x </u>=<u>  1    </u>
5 1/4    5 1/4
     x = 4/21
3(4/21) - 2y = 1
 4/7 - 2y = 1
<u>-4/7         -4/7</u>
         -2y = 3/7
         -<u>2y</u> = <u>3/7</u>
          -2      -2
           y = -3/14
(x, y) = (4/21, -3/14)
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To solve for (number of years since 2010) we take logs of both sides

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Step-by-step explanation:

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