Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

Hence the bounds of the interval are found as follows:


The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
Answer:
The median, because the data distribution is skewed to the right
Step-by-step explanation:
If the longer part of the box is to the right (or above) the median, the data is said to be skewed right. If the longer part is to the left (or below) the median, the data is skewed left. The data is skewed right. The median would be a better estimate, because one or two numbers on the high end will cause the numbers to be skewed to the right, and the mean to be high
There are 37 balloons total and there are 7 orange balloons. Therefore, the probability is 7/37.