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3 years ago

Select the possible values

Mathematics

1 answer:

svetlana [45]3 years ago

3 0

Answer:

all exept 1

Step-by-step explanation:

blah blah blah

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A university has 28,980 students. In a random sample of 180 students, 12 speak three or more languages. Predict the number of st

anygoal [31]

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3 years ago

Instructions:Drag the tiles to the correct boxes to complete the pairs. Match each polynomial function with one of its factors.

Svetach [21]

We have the following functions:
f (x) = x3 - 3x2 - 13x + 15
f (x) = x4 + 3x3 - 8x2 + 5x - 25
f (x) = x3 - 2x2 - x + 2
f (x) = -x3 + 13x - 12
Factoring we have:
f (x) = x3 - 3x2 - 13x + 15 -------> x + 3
f (x) = x4 + 3x3 - 8x2 + 5x - 25 -> x + 5
f (x) = x3 - 2x2 - x + 2 ------------> x - 2
f (x) = -x3 + 13x - 12 -------------> x + 4

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4 years ago

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A minivan traveling at 50 mph and a motorcycle traveling at 60 mph cover the same distance. It takes the

telo118 [61]

I hope this helps you

distance is X

motorcycle 60 mph and times is t

minivan 50 mph and times is t+1

X=60.t

X=50(t+1)

60t=50t+50

10t=50

t=5 hour

t+1=6 hour

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3 years ago

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In a prior sample of U.S. adults, the Center for Disease Control (CDC), found that 8% of the people in this sample had pinworm b

kow [346]

Answer: a) 453 b) 1537

Step-by-step explanation:

As per given , we have

Margin of error : E= 0.025

Critical value for 95% confidence interval : $z_{\alpha/2}=1.96$

a) The prior estimate of population proportion : p=0.08

Required sample size :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.08(1-0.08)(\dfrac{1.96}{0.025})^2\\\\=452.386816\approx453$

The minimum sample size is 453 U.S. adults.

b) Since the prior estimate of population proportion is not available , so we take p= 0.5

Required sample size :-

$n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.96}{0.025})^2\\\\=1536.64\approx1537$

The minimum sample size is 1537 U.S. adults.

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4 years ago

It has been observed that a large percentage of professional hockey players have birthdays in the first part of the year. It has

vagabundo [1.1K]

Answer:

$\mu = 127$

$\sigma = 9.76$

$z-score = 3.18$

Yes, 158 players out of 508 is an unusual number of men born in the first 3 months of the year because the z score of 158 is greater than 3( Note :the probability of z-score = 3 is 97%)

The correct option is option 3

Step-by-step explanation:

From the question we are told that

The population proportion is p = 0.25

The sample size is n = 508

Generally the mean is mathematically represented as

$\mu = np$

=> $\mu = 508 * 0.25$

=> $\mu = 127$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{ np (1-p)}$

=> $\sigma = \sqrt{ 508 * 0.25 (1-0.25)}$

=> $\sigma = 9.76$

Generally the z-score of 158 is mathematically represented as

$z-score = \frac{158 - 127}{9.76}$

=> $z-score = \frac{158 - 127}{9.76}$

=> $z-score = 3.18$

Yes, 158 players out of 508 is an unusual number of men born in the first 3 months of the year because the z score of 158 is greater than 3( Note :the probability of z-score = 3 is 97%)

What this means is that the almost the whole professional hockey league player are born in the first month which is unusual

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3 years ago