Question

In 1923, the United States Army (there was no United States Air Force at that time) set a record for in-flight refueling of airplanes. Using two refueling planes, an Airco DH-4B biplane was able to remain in flight for 37 h . During the flight, the refueling planes were able to air-transfer a total of 687 gallons of fuel to the plane in 9 refueling transfers. Assume that the refueling nozzle had a diameter of 1.45 in and each refueling took 2.45 min to perform. Calculate the velocity of the fuel through the nozzle. Assume that the fuel filled the entire cross-sectional area of the nozzle.

Answer 1

Answer:

Explanation:

Total time of transfer oil fuel = 2.45 x 9 = 22.05 minutes

= 22.05 x 60

= 1323 s

Total volume of ful transferred = 687 gallon

= .0037854 x 687

= 2.6 m³

radius of pipe = .5 x 1.45 inch

= .5 x 1.45 x 2.54 x 10⁻² m

r = .018415 m

cross sectional area

= π r²

a = 3.14 x .018415²

= 10.648 x 10⁻⁴ m²

If v be the velocity

volume of fuel coming out  a x v x t  , a is cross sectional area , v is velocity and t is time .

10.648 x 10⁻⁴ x v x 1323  = 2.6

v = 1.845 m / s