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inessss [21]
3 years ago
7

In this problem, you will use your prior knowledge to derive one of the most important relationships in mechanics: the work-ener

gy theorem. We will start with a special case: a particle of mass m moving in the x direction at constant acceleration a. During a certain interval of time, the particle accelerates from vi to vf, undergoing displacement s given by s=xf−xi.
Required:
a. Find the accerlation a of the particle
b. Find the force F acting on the particle
c. Find the net work W done on the particle by the external forces during the particle's motion.
Physics
1 answer:
Leya [2.2K]3 years ago
4 0

Answer:

Explanation:

a )

Work done by force = change in kinetic energy

F x s =  ( vf² - vi² ) / 2m

F =  ( vf² - vi² ) / 2ms

acceleration = ( vf² - vi² ) / 2m²s

b )

F = ( vf² - vi² ) / 2ms [ calculated above ]

c )

Work done by force

= change in kinetic energy

= ( vf² - vi² ) / 2m

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