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inessss [21]
3 years ago
7

In this problem, you will use your prior knowledge to derive one of the most important relationships in mechanics: the work-ener

gy theorem. We will start with a special case: a particle of mass m moving in the x direction at constant acceleration a. During a certain interval of time, the particle accelerates from vi to vf, undergoing displacement s given by s=xf−xi.
Required:
a. Find the accerlation a of the particle
b. Find the force F acting on the particle
c. Find the net work W done on the particle by the external forces during the particle's motion.
Physics
1 answer:
Leya [2.2K]3 years ago
4 0

Answer:

Explanation:

a )

Work done by force = change in kinetic energy

F x s =  ( vf² - vi² ) / 2m

F =  ( vf² - vi² ) / 2ms

acceleration = ( vf² - vi² ) / 2m²s

b )

F = ( vf² - vi² ) / 2ms [ calculated above ]

c )

Work done by force

= change in kinetic energy

= ( vf² - vi² ) / 2m

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Its B 4ohM
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4 years ago
What could be used as another word for electrical potential
tekilochka [14]

Answer:

hey mate

answer is probably voltage as per me

as

Explanation:

Voltage, electric potential difference, electric pressure or electric tension is the difference in electric potential between two points, which is defined as the work needed per unit of charge to move a test charge between the two points

5 0
3 years ago
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A ladder of length 10 is leaning against a wall. The vertical wall is frictionless while the horizontal surface is rough. The an
bogdanovich [222]

Answer:

105.1N

Explanation:

According to the newton second law

\sum F_x = ma_x\\F_m - F_f = ma_x\\

Since the acceleration is zero, then;

F_m - F_f = 0\\Fm = F_f\\

Since;

F_m = mg sin \theta, \  hence \ F_f = mg sin \theta

Given the following

mass of ladder m = 14kg

acceleration due to gravity g = 9.8m/s²

θ = 50°

Substitute

F_f = 14(9.8)sin50\\F_f = 14(7.5072)\\F_f = 105.1N\\

Hence the magnitude of the friction force (in N) exerted on the ladder in the point of contact with the horizontal surface is 105.1N

8 0
3 years ago
Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to
Deffense [45]

Answer:

P2 = 128,205 pascal.

Explanation:

<u>Given the following data;</u>

Original Pressure, P1 = 100,000 pascals

Original Temperature, T1 = 273K

New Temperature, T2 = 350K

To find new pressure P2, we would use Gay Lussac' law.

<em>Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas. </em>

Mathematically, Gay Lussac's law is given by;

PT = K

Where;

  • P represents pressure.
  • T represents temperature.
  • K is the constant of proportionality.

\frac{P1}{T1} = \frac{P2}{T2}

<em>Making P2 as the subject formula, we have;</em>

P_{2}= \frac{P1}{T1} * T_{2}

Substituting into the equation, we have;

P_{2}= \frac{100000}{273} * 350

P_{2}= 366.3004* 350

P2 = 128205.13 ≈ 128205 pascal.

<em>Therefore, the pressure inside the hot water bottle is 128,205 pascal. </em>

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