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blagie [28]
4 years ago
15

The density of a rock is 2 g/mL and its’ been displaced in water with a volume of 25 mL. Calculate the mass of the rock in grams

.
Physics
1 answer:
Ludmilka [50]4 years ago
4 0

Answer:

d =  

m

V

m = d×V

V =  

m

d

DENSITY

Density is defined as mass per unit volume.

d =  

m

V

Example:

A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?

Step 1: Calculate the volume

V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³

Step 2: Calculate the density

d =  

m

V

=  

433

g

200

c

m

³

= 2.16 g/cm³

MASS

d =  

m

V

We can rearrange this to get the expression for the mass.

m = d×V

Example:

If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?

m = d×V = 500 mL ×  

1.11

g

1

m

L

= 555 g

VOLUME

d =  

m

V

We can rearrange this to get the expression for the volume.

V =  

m

d

Example:

What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.

Step 1: Convert kilograms to grams.

14.83 kg ×  

1000

g

1

k

g

= 14 830 g

Step 2: Calculate the volume.

V =  

m

d

= 14 830 g ×  

1

c

m

³

19.32

g

= 767.6 cm³

Explanation: got it from a site

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If the block is subjected to the force of F = 500 N, determine its velocity at s = 0.5 m. When s = 0, the block is at rest and t
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Answer:

The velocity is  4.6 m/s^2

Explanation:

Given:

Force = 500N

Distance  s= 0

To find :

Its velocity at s = 0.5 m

Solution:

\sum F_{x}=m a

F\left(\frac{4}{5}\right)-F_{S}=13 a

500\left(\frac{4}{5}\right)-\left(k_{s}\right)=13 a

400-(500 s)=13 a

a = \frac{400 -(500s)}{13}

a = (30.77 -38.46s) m/s^2

Using the relation,

a=\frac{d v}{d t}=\frac{d v}{d s} \times \frac{d s}{d t}

a=v \frac{d v}{d s}

v d v=a d s

Now integrating on both sides

\int_{0}^{v} v d v=\int_{0}^{0.5} a d s

\int_{0}^{v} v d v=\int_{0}^{0.5}(30.77-38.46 s) d s

\left[\frac{v^{2}}{2}\right]_{0}^{2}=\left[\left(30.77 s-19.23 s^{2}\right)\right]_{0}^{0.5}

\left[\frac{v^{2}}{2}\right]=\left[\left(30.77(0.5)-19.23(0.5)^{2}\right)\right]

\left[\frac{v^{2}}{2}\right]=[15.385-4.807]

\left[\frac{v^{2}}{2}\right]=10.578

v^{2}=10.578 \times 2

v^{2}=21.15

v = \sqrt{21.15}

v = 4.6 m/s^2

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